Homework Help is Here – Start Your Trial Now!
Science
Advanced Physics
Problem 1 A 0.20 kg/s of air are compressed isothermally from P1= 100 kPa and V1= 0.15 m3/s to P2= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of ʋ1 = 15 m/s and ʋ2 = 60 m/s, respectively. Solve with comple units and formula.

Problem 1 A 0.20 kg/s of air are compressed isothermally from P1= 100 kPa and V1= 0.15 m3/s to P2= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of ʋ1 = 15 m/s and ʋ2 = 60 m/s, respectively. Solve with comple units and formula.

icon
Related questions
Question

Problem 1
A 0.20 kg/s of air are compressed isothermally from P1= 100 kPa and V1= 0.15 m3/s to P2= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of ʋ1 = 15 m/s and ʋ2 = 60 m/s, respectively. Solve with comple units and formula.

Problem 2
Air in a piston-cylinder occupies an intial volume of 0.15 m3 at a pressure of 560 kPa. The air expands in a reversible adiabatic process. Air doing the work on the piston caused the volume to increase until it reaches 0.30 m3. Determine the work in the system. Solve with comple units and formula.

 

Problem 1 A 0.20 kg/s of air are compressed isothermally from P,= 100 kPa and V,= 0.15 m³/s to P,= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of v1 respectively. %3D = 15 m/s and v, = 60 m/s, Problem 2 Air in a piston-cylinder occupies an intial volume of 0.15 m3 at a pressure of 560 kPa. The air expands in a reversible adiabatic process. Air doing the work on the piston caused the volume to increase until it reaches 0.30 m³. Determine the work in the system.
Transcribed Image Text:Problem 1 A 0.20 kg/s of air are compressed isothermally from P,= 100 kPa and V,= 0.15 m³/s to P,= 700 kPa. Determine: The work in kW and the change in entropy in kJ/s-K for (a) closed or non-flow process and (b) open or steady flow process with initial and final velocity of v1 respectively. %3D = 15 m/s and v, = 60 m/s, Problem 2 Air in a piston-cylinder occupies an intial volume of 0.15 m3 at a pressure of 560 kPa. The air expands in a reversible adiabatic process. Air doing the work on the piston caused the volume to increase until it reaches 0.30 m³. Determine the work in the system.
Expert Solution
steps

Step by step

Solved in 2 steps

SEE SOLUTIONCheck out a sample Q&A here
Blurred answer