Problem 1: Given f(x) = e* that is defined over [0, 2] with h = 0.5, to solve questions (1 to 6) (1) The maximum order of the polynomial that we can get from the data is: a. 2 b. 3 c. 4 d. 5 (2) The absolute error If (1.2) - P₁(1.2) / using Lagrangian interpolation is: a. 3.4237 b.-3.3201 c. -0.1036 d. 0.1036 (3) The value of f(x₁, x2] using divided difference is: a. 1.2974 b. 1.6487 c. 2.1392 d. 2.7183

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter5: Inverse, Exponential, And Logarithmic Functions
Section5.6: Exponential And Logarithmic Equations
Problem 64E
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Problem 1: Given f(x) = e* that is defined over [0, 2] with h = 0.5, to solve questions (1 to 6)
(1) The maximum order of the polynomial that we can get from the data is:
a. 2
b. 3
C. 4
d. 5
(2) The absolute error If (1.2) - P₁(1.2) / using Lagrangian interpolation is:
a. 3.4237
b.-3.3201
C. -0.1036
d. 0.1036
(3) The value of f(x1, x2] using divided difference is:
a. 1.2974
b. 1.6487
c. 2.1392
(4) The first derivative
a. 2.5601
of P₂(x) at (x = 1) using divided difference is:
b. 2.8330
c. 2.7183
d. 2.7183
(6) The most suitable points (x-values) to find P₂ (1.3) are:
a. (0, 0.5, 1)
b. (0.5, 1, 1.5)
c. (1, 1.5, 2)
d. 2.1392
(5) The value of A² f₁ using function difference (NGF) interpolation is:
a. 1.0696
b. 0.6938
C. 0.6487
d. 0.4209
d. (0, 1, 2)
Transcribed Image Text:Problem 1: Given f(x) = e* that is defined over [0, 2] with h = 0.5, to solve questions (1 to 6) (1) The maximum order of the polynomial that we can get from the data is: a. 2 b. 3 C. 4 d. 5 (2) The absolute error If (1.2) - P₁(1.2) / using Lagrangian interpolation is: a. 3.4237 b.-3.3201 C. -0.1036 d. 0.1036 (3) The value of f(x1, x2] using divided difference is: a. 1.2974 b. 1.6487 c. 2.1392 (4) The first derivative a. 2.5601 of P₂(x) at (x = 1) using divided difference is: b. 2.8330 c. 2.7183 d. 2.7183 (6) The most suitable points (x-values) to find P₂ (1.3) are: a. (0, 0.5, 1) b. (0.5, 1, 1.5) c. (1, 1.5, 2) d. 2.1392 (5) The value of A² f₁ using function difference (NGF) interpolation is: a. 1.0696 b. 0.6938 C. 0.6487 d. 0.4209 d. (0, 1, 2)
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