Problem 1. Prove that for a vacuum-dielectric interface at glancing incidence r-1 (see Fig. 4.49 from textbook, also on slide 7 in Lecture 4). In the same figure, if a is the angle that the curve r (0) makes with the vertical at 0, = 90°, then: Vn2 – 1 tana 2 1.0 0.5 Op -0.5 56.3° -1.0 30 60 90 0; (degrees) Figure 4.49 The amplitude coefficients of reflection and transmission as a function of incident angle. These correspond to external reflection n, > n at an air-glass interface (n = 1.5). Amplitude coefficients

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Problem 1. Prove that for a vacuum-dielectric interface at glancing incidence ri→-1 (see Fig. 4.49 from
textbook, also on slide 7 in Lecture 4). In the same figure, if a is the angle that the curve r(0.) makes
with the vertical at 0; = 90°, then:
Vn2 – 1
tana,
2
1.0
0.5
Op
-0.5
56.3°
-1.0
30
60
90
0; (degrees)
Figure 4.49 The amplitude coefficients of reflection and transmission as
a function of incident angle. These correspond to external reflection n; > n;
at an air-glass interface (n = 1.5).
Amplitude coefficients
of
Transcribed Image Text:Problem 1. Prove that for a vacuum-dielectric interface at glancing incidence ri→-1 (see Fig. 4.49 from textbook, also on slide 7 in Lecture 4). In the same figure, if a is the angle that the curve r(0.) makes with the vertical at 0; = 90°, then: Vn2 – 1 tana, 2 1.0 0.5 Op -0.5 56.3° -1.0 30 60 90 0; (degrees) Figure 4.49 The amplitude coefficients of reflection and transmission as a function of incident angle. These correspond to external reflection n; > n; at an air-glass interface (n = 1.5). Amplitude coefficients of
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