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- The packet matching conservative algorithm is conservative because the packet matching condition is too restrictive. Question 10 options: True Falseif a noiseless channel, if the bandwidth is 2 KHZ and there are 16 voltage levels, what is thw Data rate? a. 8kbits/sec b. 16 kbits/sec c. 8000 bits/sec d. 12 kbits/sec if the frequency is 1014 , then the wevelength a. 3x10-6 meter b. 3x10-8 meter c. 3x10-6 meter d. 3x10-5 meterState and prove Baye's theorem.
- kindly don't copy from chegg and please explain clearly. Do using your common sense otherwise I wiil downvote you. If you can't solve just skipANSWER SHOULD BE: 5.977 A, 35.72 JPLEASE SHOW THE STEP-BY-STEP SOLUTIONACTIVITY : CODING Suppose the following messages are source encoded given by the table. Message Encoded Bits UP 00 DOWN 01 LEFT 10 RIGHT 11 Complete the given table by writing the source encoded message of the following set of directions. Set of Directions Source Encoding LEFT - UP - RIGHT - DOWN 1.) UP - DOWN - UP - RIGHT 2.) DOWN - DOWN - RIGHT - LEFT 3.) UP - DOWN - LEFT - RIGHT 4.) RIGHT - LEFT - RIGHT - UP 5.) Decode the set of directions given by the message received. Message Received Decoded Message 10010011 1.) 01010010 2.) 11000110 3.) 01100111 4.) 00101111 5.) III. Complete the given table by writing the channel encoded message by using parity check of adding 1 bit in the message. Message Source Encoding Channel Encoding ALLY 000 1.) ENEMY 011 2.) ATTACK 100 3.) RETREAT 111 4.) SURRENDER 101 5.)…
- DISCRETE SYSTEM PROBLEM( NEED NEAT HANDWRITTEN SOLUTION ONLY OTHERWISE DOWNVOTE).In a broadcasting studio, a 1000kHz carrier is modulated by an audio signal offrequency range100-5000Hz. Find (i) width or frequency range of side bands(ii) maximum and minimum frequencies of USB (iii) maximum and minimumfrequencies of LSB and (iv) width of the channel.24 - Which of the following statements regarding asynchronous circuits is incorrect? a) O Updates are fast because they depend on instantaneous and individual propagation delays. b) O Power consumption is low. c) Because the memory elements are updated at different times, their design and analysis are difficult. d) O Memory elements are updated at the same time, so they are easy to design and analyze.
- V_ds=???(need handwritten only ,otherwise downvote.)Answer both subparts and dont copyQuestion Vvvv Modulation types in wireless communication systems? Explain in detail in terms of bandwidth requirements and resisting the disruptive effects in the system Full explain this question and tex t typing work only We should answer our question within 2 hours takes more time then we will reduce Rating Dont ignore this line