PROBLEM 1. The long chord of a compound curve is 120m long which makes an angle of 14° from the tangent of the first curve passing through the PC and 20° from the tangent of the second curve passing through the PT. If the common tangent is parallel to the long chord. a.) Compute the length of chord from PC to PCC b.) Compute the length of chord from PCC to PT c.) Compute the difference in radius of the first and second curve.

Traffic and Highway Engineering
5th Edition
ISBN:9781305156241
Author:Garber, Nicholas J.
Publisher:Garber, Nicholas J.
Chapter15: Geometric Design Of Highway Facilities
Section: Chapter Questions
Problem 13P
icon
Related questions
Question
ans No. 1 only. asap
PROBLEM 1. The long chord of a compound curve is 120m long which makes an angle of 14° from
the tangent of the first curve passing through the PC and 20° from the tangent of the second curve
passing through the PT. If the common tangent is parallel to the long chord.
a.) Compute the length of chord from PC to PC
b.) Compute the length of chord from PCC to PT
c.) Compute the difference in radius of the first and second curve.
PROBLEM 2. A compound curve passes thru a common tangent AB having a length of 300m. The
radius of the first curve is equal to 290m and a central angle of 42°. If the angle of intersection of
the curve is 70°36'.
a.) Compute for the Radius of the second curve
b.) If the stationing of the PI is at (20+542.2), Compute for the Stationing of PT..
PROBLEM 3. Two parallel tangents 20m apart are to be connected by a reversed curve with equal
radius. The tangent of the 1st curve is 37.817m which is along the tangents of common direction.
The stationing of the PC is 10+200.
a.) Compute for the long chord.
b.) Compute for the common radius.
c.) Compute for the stationing of PT.
PROBLEM 4. The tangents of a simple curve have bearings of N 20° E and N 80° E respectively.
The radius of the curve is 200 m.
Determine the following:
a. The external distance of the curve.
b. The middle ordinate of the curve.
c. The stationing of point A on the curve having a deflection angle of 6 from the P.C. which
is at 1+200.00.
PROBLEM 5. A simple curve have tangents XY and YZ intersecting at a common point Y. XY has
an azimuth of 180° and YZ has an azimuth of 230°. The stationing of the point of curvature at X is
10+140.26. If the degree of curve of the simple curve is 4°.
Determine the following:
d. The length of the long chord from X..
e. The tangent distance XY.
f. The stationing at a point A on the curve on which a line passing through the center of
the curve makes an angle of 58° with the line XY, intersects the curve at point A.
Transcribed Image Text:PROBLEM 1. The long chord of a compound curve is 120m long which makes an angle of 14° from the tangent of the first curve passing through the PC and 20° from the tangent of the second curve passing through the PT. If the common tangent is parallel to the long chord. a.) Compute the length of chord from PC to PC b.) Compute the length of chord from PCC to PT c.) Compute the difference in radius of the first and second curve. PROBLEM 2. A compound curve passes thru a common tangent AB having a length of 300m. The radius of the first curve is equal to 290m and a central angle of 42°. If the angle of intersection of the curve is 70°36'. a.) Compute for the Radius of the second curve b.) If the stationing of the PI is at (20+542.2), Compute for the Stationing of PT.. PROBLEM 3. Two parallel tangents 20m apart are to be connected by a reversed curve with equal radius. The tangent of the 1st curve is 37.817m which is along the tangents of common direction. The stationing of the PC is 10+200. a.) Compute for the long chord. b.) Compute for the common radius. c.) Compute for the stationing of PT. PROBLEM 4. The tangents of a simple curve have bearings of N 20° E and N 80° E respectively. The radius of the curve is 200 m. Determine the following: a. The external distance of the curve. b. The middle ordinate of the curve. c. The stationing of point A on the curve having a deflection angle of 6 from the P.C. which is at 1+200.00. PROBLEM 5. A simple curve have tangents XY and YZ intersecting at a common point Y. XY has an azimuth of 180° and YZ has an azimuth of 230°. The stationing of the point of curvature at X is 10+140.26. If the degree of curve of the simple curve is 4°. Determine the following: d. The length of the long chord from X.. e. The tangent distance XY. f. The stationing at a point A on the curve on which a line passing through the center of the curve makes an angle of 58° with the line XY, intersects the curve at point A.
Expert Solution
steps

Step by step

Solved in 5 steps with 1 images

Blurred answer
Knowledge Booster
Interior finishes for wood light frame construction
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Traffic and Highway Engineering
Traffic and Highway Engineering
Civil Engineering
ISBN:
9781305156241
Author:
Garber, Nicholas J.
Publisher:
Cengage Learning