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Problem 2 (a) Make a table of values to graph y = Vx. Then on the same set of coordinate axes graph y =-Vx and y = -x. What pattern do you observe? How are the graphs related? y= Vx -6-5 1 2 3 4 5 6x y = -V y=\-x (b) The area under the curve y = Vx bounded below by the x-axis and on the right by x=4 is 16/3 square units. Using the ideas of graphing transformations, what do you think is the area under the curve y =v-x bounded below by the x-axis and on the left by x =-4? Justify your answer.

Problem 2 (a) Make a table of values to graph y = Vx. Then on the same set of coordinate axes graph y =-Vx and y = -x. What pattern do you observe? How are the graphs related? y= Vx -6-5 1 2 3 4 5 6x y = -V y=\-x (b) The area under the curve y = Vx bounded below by the x-axis and on the right by x=4 is 16/3 square units. Using the ideas of graphing transformations, what do you think is the area under the curve y =v-x bounded below by the x-axis and on the left by x =-4? Justify your answer.

Algebra & Trigonometry with Analytic Geometry
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter11: Topics From Analytic Geometry
Section11.3: Hyperbolas
Problem 38E
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7:32 MA 105 Group Proble... Problem 2 (a) Make a table of values to graph y = Vx. Then on the same set of coordinate axes graph y=-Vx and y = -x. What pattern do you observe? How are the graphs related? y = V -4 -6 -5 -4 -3 -2 -1 ( 5x y =-Vx y=V-x (b) The area under the curve y = Vx bounded below by the x-axis and on the right by x = 4 is 16/3 square units. Using the ideas of graphing transformations, what do you think is the area under the curve y = -x bounded below by the x-axis and on the left by x =-4? Justify your answer. Dashboard Calendar To Do Notifications Inbox
Transcribed Image Text:7:32 MA 105 Group Proble... Problem 2 (a) Make a table of values to graph y = Vx. Then on the same set of coordinate axes graph y=-Vx and y = -x. What pattern do you observe? How are the graphs related? y = V -4 -6 -5 -4 -3 -2 -1 ( 5x y =-Vx y=V-x (b) The area under the curve y = Vx bounded below by the x-axis and on the right by x = 4 is 16/3 square units. Using the ideas of graphing transformations, what do you think is the area under the curve y = -x bounded below by the x-axis and on the left by x =-4? Justify your answer. Dashboard Calendar To Do Notifications Inbox
Expert Solution
Step 1

(a)

The given equations are:

y=x             ...(i)y=-x           ...(ii)y=-x           ...(iii)

Equation (i) and (ii) are defined for all x≥0 and equation (iii) is defined for all x≤0.

Putting x=0 in (i), we get

y=0=0

Putting x=1 in (i), we get

y=1=1

Putting x=4 in (i), we get

y=4=2

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