Problem 3 An equal-leg angle L8x8x5/8 tension member is subjected to tensile loads. The connection between the member and the gusset plate is made by using 4-1 1/8" diameter bolts in one row as shown. Assume Fy = 36 ksi and Fu = 58 ksi. Use U = 0.8. Determine the controlling design tensile strength OPn of the tension member (the smallest OPn from yielding, rupture, and block shear) 1¾" 2½" 3 spaces @ 2½" L 8x8x5/8 1 1/8" diameter bolts
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- Steel design. The lap joint shown consist of bolts 22mm in diameter in 25mm diameter holes, The plates are A36 steel with Fy=250MPa, and Fu=400MPa. Use x1=50 mm ,x2= 160mm ,x3=60mm and plate thickness t=12mm for this problem. The allowable stress are: Bearing stress on project are,Fc=1.5Fu Tension on the net area of plates,Ft=0.5Fu Shear on the plates, Fv=0.3Fu Shear strength of bolt,Fv=210MPa Det. the value of Load P based on bolt shear Det. the value of Load P base on bearing on projected area on plate. Det. the value of load P based on block shearA double channel shape is used as a tension member. The channels are bolted to a gusset plate with 22mm diameter bolts. Fy-channel = 345 MPa, Fu-channel = 450 MPa Fy-plate = 248 MPa, Fu-plate = 400 MPa Achannel = 3555 mm^2, tw = 12.18 mm, Shear lag factor = 0.90 B. Determine the allowable tensile strength of the tension member based on its gross area.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0.a) Determine the design tensile strength of the section based on yielding of the gross area.b) Determine the critical net area of the connection shown.
- A double channel shape is used as a tension member. The channels are bolted to a gusset plate with 22mm diameter bolts. Fy-channel = 345 MPa, Fu-channel = 450 MPa Fy-plate = 248 MPa, Fu-plate = 400 MPa Achannel = 3555 mm^2, tw = 12.18 mm, Shear lag factor = 0.90 D. Determine the allowable tensile strength of the tension member based on its net area.A 15" x 3/8" bar of A572 Gr. 50 steel is used as a tension member. It is connected to a gusset plate with 7/8-in diameter bolts as shown in the figure. Use s = 2.0 and g = 3.0. Determine the critical net area of the connection shown. Determine the design tensile strength of the section based on yielding of the gross area.A double-angle shape, 2L7 3 4 3 3⁄8, is used as a tension member. The twoangles are connected to a gusset plate with 7⁄8-inch-diameter bolts throughthe 7-inch legs, as shown in Figure P3.4-5. A572 Grade 50 steel is used.a. Compute the design strength.b. Compute the allowable strength.
- A channel shape, C8 × 18.75, is used as a tension member. The channels are boltedto a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs?STAGGERED CONNECTIONS: A PLATE WITH WIDTH OF 400 mm AND THICKNESS OF 12 mm IS TO BE CONNECTED TO A PLATE OF THE SAME WIDTH AND THICKNESS BY 34 mm DIAMETER BOLTS, AS SHOWN IN THE FIGURE. THE HOLES ARE 2 mm LARGER THAN THE BOLT DIAMETER. THE PLATE IS A36 STEEL WITH YIELD STRENGTH Fy = 248 MPa. ASSUME ALLOWABLE TENSILE STRESS ON NET AREA IS 0.60Fy. IT IS REQUIRED TO DETERMINE THE VALUE OF b SUCH THAT THE NET WIDTH ALONG BOLTS 1-2-3-4 IS EQUAL TO THE NET WIDTH ALONG BOLTS 1-2-4. a. CALCULATE THE VALUE OF b IN MILLIMETERS. b. CALCULATE THE VALUE OF THE NET AREA FOR TENSION IN PLATES IN SQUARE MILLIMETERS. c. CALCULATE THE VALUE OF P SO THAT THE ALLOWABLE TENSILE STRESS ON NET AREA WILL NOT BE EXCEEDED.A W14X120 is used as a tension member in atruss. The flanges of the member are connected to a gusset plate by ¾ inch boltas shown below. Use A36 steel with Fy=36 ksi and Fu=58 ksi A. Determine the Yielding Capacity of the section based on LRFD (kips) Round your answer to 2 decimal places. c. Determine the Tensile Rupture capacity of the section based on LRFD need answer please
- A channel shape, C8 × 18.75, is used as a tension member. The channels are bolted to a 10mm-thick gusset plate with 22mm- diameter bolts. The tension member is A572 Grade 50 steel (Fy = 345 MPa, Fu = 450 MPa) and the gusset plate is A36 (Fy = 250 MPa, Fu = 410MPa). What is the ult. capacity of the channel in kips, if yielding on the gross area governs? What is the ult. capacity of the channel in kips, if fracture on the net area governs? What is the ult. capacity of the gusset plate in kips, if block shear governs? What is the effective net area of the channel section, in square millimeters?subject: Steel Design 1. A992 steel is used for the tension member shown. The bolts are 3/4 inch in diameter. The connection is to a 3/8 in.thick gusset plate. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the effective net are.The bolts in the lap joint shown are 22mm in diameter and 25mm diameter holes. The plates are A36 steel with Fy = 250MPa and Fu = 400Mpa. For this problem, x1 = 500mm, x2 = 160mm, x3 = 60mm and t = 12mm. The allowable stresses are: Bearing Stress on projected area of the plates Fp = 1.5Fu Tension on net area of plates, Ft = 0.5Fu Shear on plates, Fy= 0.3Fu Shear strength of bolt, Fv= 210 Mpa a.) Determine the value of P based on bolt shear b.) Determine the value of load P based on bearing on projected area on plate (area in contact with the plate and bolts) c.) Determine the value of P based on block shear (use net area for block shear and use the diameter of hole)