Problem 5 A cylindrical can with closed bottom and closed top is to be constructed to have a volume of 200 cubic inches. The material used to make the bottom and top costs $0.06 per square inch, and the material to make the side curved surface costs $0.03 per square inch. The curved surface can be unrolled to form a rectangle having the same height of the can and a length equal to the circumference of the Area of curved surface A= (7d)h h. h = height of can Volume of can d= diameter can. The top and bottom are circles with the same diameter as the can. Find the dimensions of the can (height and -h 4 Area of top and bottom = nd diameter) that minimize the total cost and find the cost. See figure.

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter9: Surfaces And Solids
Section9.3: Cylinders And Cones
Problem 7E: The tin can shown at the right has the indicated dimensions. Estimate the number of square inches of...
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Problem 5
A cylindrical can with closed bottom and closed top is to
be constructed to have a volume of 200 cubic inches. The
material used to make the bottom and top costs $0.06 per
square inch, and the material to make the side curved
surface costs $0.03 per square inch. The curved surface
can be unrolled to form a rectangle having the same height
of the can and a length equal to the circumference of the
Area of curved surface
A= (7d)h
h.
h = height of can
Volume of can
d= diameter
can. The top and bottom are circles with the same diameter
as the can. Find the dimensions of the can (height and
-h
4
Area of top and bottom =
nd
diameter) that minimize the total cost and find the cost.
See figure.
Transcribed Image Text:Problem 5 A cylindrical can with closed bottom and closed top is to be constructed to have a volume of 200 cubic inches. The material used to make the bottom and top costs $0.06 per square inch, and the material to make the side curved surface costs $0.03 per square inch. The curved surface can be unrolled to form a rectangle having the same height of the can and a length equal to the circumference of the Area of curved surface A= (7d)h h. h = height of can Volume of can d= diameter can. The top and bottom are circles with the same diameter as the can. Find the dimensions of the can (height and -h 4 Area of top and bottom = nd diameter) that minimize the total cost and find the cost. See figure.
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