Problem 5.10 Using the expression for V given by equation (5.9), obtain V .V in cylindrical coordinates. Note that the derivatives also act on the unit vectors, as in going from equation (2.8) to (2.9). Answer: V · V =(rV,)+ p ap av az +
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V = ê1;
hi Oqi
1 д
+ ёз
h2 aq2
hz dq3](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa957bed-8d63-4ec5-83f0-11dee37c879a%2F334d6972-bfe0-453f-aaf5-852a8e16e7cd%2F44pr8hd_processed.jpeg&w=3840&q=75)
![Problem 5.10 Using the expression for V given by equation (5.9), obtain
V.V in cylindrical coordinates. Note that the derivatives also act on the unit
vectors, as in going from equation (2.8) to (2.9). Answer: V · V =1 (rV,) +
p ap
av.
az
+](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffa957bed-8d63-4ec5-83f0-11dee37c879a%2F334d6972-bfe0-453f-aaf5-852a8e16e7cd%2F4qy83q9_processed.jpeg&w=3840&q=75)
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