Answered: Problems 8-9, Find the r and y… | bartleby

Linear Algebra: A Modern Introduction

Linear Algebra: A Modern Introduction

4th Edition

ISBN:9781285463247

Author:David Poole

Publisher:David Poole

Chapter4: Eigenvalues And Eigenvectors

Section4.2: Determinants

Problem 11AEXP

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Kindly assist at your earliest convenience.

Problems 8-9, Find the r and y intercepts of the given equation. Use the intercepts to sketch the
graph of the equation.
8. 3r-4y -24
%3D
T-intercept:
y-intercpet:
-109-8-7-0-7-4-3-2-
1 23456 7 8 9 ib

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Only problem 30
The equation of the line that goes through the point (2,7) and is parallel to the line 5x+3y=4 can be written in the form y=mx+b
If i have the problem 4y - x = -4 , how do I write this in slope intercept form?
The equation of the line that goes through the point (1,1) and is perpendicular to the line 4x+4y=4 can be written in the form y=mx+bwhere m is: _____ and where b is: ____
Line A is given by the equation: 8x + 7y = -12 Line B is given by the equation: 4x + 3y = -21 What is the x coordinate of the intersection point of line A and line B? (Round your answer to the nearest hundredth)
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The properties in Problem 83 provide us with another way to write the equation of a line parallel or perpendicular to a given line that contains a given point not on the line. For example, suppose that we want the equation of the line perpendicular to 3x + 4y = 6 that contains the point (1, 2). The form 4x - 3y = k, where k is a constant, represents a family of lines perpendicular to 3x + 4y = 6 because we have satisfied the condition AA' = -BB'. Therefore, to find what specific line of the family contains (1, 2), we substitute 1 for x and 2 for y to determine k.4x - 3y = k4(1) - 3(2) = k-2 = k Thus the equation of the desired line is 4x - 3y = -2. Use the properties from Problem 83 to help write the equation of each of the following lines.(a) Contains (1, 8) and is parallel to 2x + 3y = 6(b) Contains (-1, 4) and is parallel to x - 2y = 4(c) Contains (2, -7) and is perpendicular to 3x - 5y = 10(d) Contains (-1, -4) and is perpendicular to 2x + 5y = 12
The equation of the line that goes through the point (1,8) and is parallel to the line 3x+2y=4 can be written in the form y=mxtb I got m=-3/2 I'm having trouble calculating what b is?
Given Problem
where is the solution for question iii
Find an equation of the red line if a=−3, b=9 and an equation of the blue curve is y=x^2+8

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