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- will give thumbs up Python Big-O Coding Exercise Find f(n), T(n) and the Big-O Total complexity Pls answer only if u know big-oAnalyze the following codes for Time and space complexity. Determine Big O for the following code fragments in the average case. Assume that all variables are of type int. (i) sum = 0; if (EVEN(n)) for (i=0; i<n; i++) sum++; else sum = sum + n; sum1 = 0;Assume that you were given N cents (N is an integer) and you were asked to break up the N cents into coins consisting of 1 cent, 2 cents and 5 cents. Write a dynamicprogramming based recursive algorithm, which returns the smallest (optimal) number of coins needed to solve this problem. For example, if your algorithm is called A, and N = 13, then A(N) = A(13) returns 4, since 5+5+2+1 = 13 used the smallest (optimal) number of coins. In contrast, 5+5+1+1+1 is not an optimal answer.
- Question No 2: Compare the complexities of the following two pieces of code using the cyclomatic complexity metrics. What conclusions can you draw about relative complexity of the code? Code A Code B int i = 1; int j = 1; while (i <= 5) { int i = 2; Playacard(i); if (j =i); if (playhaswon(i)) j++; else i++; i++; else System.out.println(j); i--; i++; }please answer this. thanks a. Give analysis of the running time (Big-Oh will do) and the space complexity. b. Implement the code in C language and give the running time for threevalues of N (N must be > 5). c. Compare your analysis with the actual running times. (3.) sum = 0; for( i = 0; i < n; ++i ) for( j = 0; j < i * i; ++j ) for( k = 0; k < j; ++k ) ++sum;please answer this. thanks a. Give analysis of the running time (Big-Oh will do) and the space complexity. b. Implement the code in C language and give the running time for threevalues of N (N must be > 5). c. Compare your analysis with the actual running times. (2...) sum = 0; for( i = 0; i < n; ++i ) for( j = 0; j < n * n; ++j ) ++sum;
- a) Consider a recursive function to return the Number of Binary Digits in the Binary Representation of a Positive Decimal Integer (n) using a recursive algorithm. int Process (int n) { if (n == 1) return 1; else return (Extra() + Process (n/4) + Process (n/4)); } Given that Extra(n) is a function of O(n)1) Find T(n) = number of arithmetic operations. 2) Calculate the complexity of this algorithm using Back Substitution.Please give the big-O time complexity of the following snippet of code and state the reason why it is so. I'll give upvote if correct, thank you.Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n^2). Apply dynamic programming. Do not use recursion/memoization. Make sure ALL test cases return expected outputs. Sample Input 04 412340123 Sample Output 013715 Explanation 0You are given the sequence 1,2,3,4.F0 = A0 = 1F1 = A1 + F0 = 2 + 1 = 3F2 = A2 + F1 + F0 = 3 + 3 + 1 = 7F3 = A3 + F2 + F1 + F0 = 4 + 7 + 3 + 1 = 15 The actual code def solve(k,a): MOD = 1000000007 # compute and return answer here q, n = list(map(int,input().rstrip().split(" ")))a = [int(input().rstrip()) for i in range(n)]outs = []for i in range(q): k = int(input().rstrip()) outs.append(solve(k,a))print("{}".format("\n".join(list(map(str,outs)))))
- Mention cyclomatic complexity briefly.Information is present in the screenshot and below. Based on that need help in solving the code for this problem in python. The time complexity has to be as less as possible (nlogn or n at best, no n2) and runtime should be under 1 second. Apply dynamic programming. Do not use recursion. Make sure ALL test cases return expected outputs. Output FormatFor each query, output one line containing an integer Dn. The number must be output mod (109 + 7). Sample Input 0:501234 Sample Output 0:10129 Edge Case: (to test against runtime and timeout error)300000 (number of queries)300000300000300000300000...and so on until there are 300,000 of them The actual code: def solve(n): MOD = 1000000007 # compute and return answer here q = int(input().rstrip()) outs = [] for i in range(q): n = int(input().rstrip()) outs.append(solve(n)) print("{}".format("\n".join(list(map(str,outs)))))In turing mahcine, the machine takes 2 natural numbers as input in unary form and outputs the integer quotient and the remainder of the integer division: (3, 5) = (2, 1) ^^^111^11111^^^ = ^^^11^1^^^ What would the functionality diagram look like? write answer in the form of {((q_0, 1), (q_0, 1, R)),((q_0, ^), (q_1, ^, L)), ......}