Prove that (a) 340 - 4, and (b) 341 – 5 are divisible by 7. (You cannot rely on a calculator in your solution.) (a) 3^{40} - 4 is divisible by 7: 3^{40} = (3^{2})^{20} = 9^{20} = mod 7 = 2^{20} = (2^{2})^{10} = 4^{10} = (4^{2})^{5} = (16)^{5} = mod 7 = 2^{5} = 32 = mode 7 = 4 3^{40} -4 4-4=0 = 3^{40} 4 is divisible by 70 (b) 3^{41} - 5 is divisible by 7:
Prove that (a) 340 - 4, and (b) 341 – 5 are divisible by 7. (You cannot rely on a calculator in your solution.) (a) 3^{40} - 4 is divisible by 7: 3^{40} = (3^{2})^{20} = 9^{20} = mod 7 = 2^{20} = (2^{2})^{10} = 4^{10} = (4^{2})^{5} = (16)^{5} = mod 7 = 2^{5} = 32 = mode 7 = 4 3^{40} -4 4-4=0 = 3^{40} 4 is divisible by 70 (b) 3^{41} - 5 is divisible by 7:
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.5: The Binomial Theorem
Problem 16E
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