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- 4.2) (L4) Give truth values for the propositional variables that cause the two expressions to have different truth values. For example, given p ∨ q and p ⊕ q, the correct answer would be p = q = T, because when p and q are both true, p ∨ q is true but p ⊕ q is false. Note that there may be more than one correct answer. r ∧ (p ∨ q) (r ∧ p) ∨ qGiven X = {1, 2, 5, 8, 9}, Y = {3, 4, 6, 7, 8}, Z = {1, 2, 4, 6, 8} and U = {1, 2, 3, 4, 5, 6, 7, 8, 9}. Findthe following: 1. (X -Z̅) ∪ Y2. (X̅ ∪ Z) ∩ Y3. (Y ∩̅Z) ∩ X4. (X ∩ Z) - (X ∪ Y)5. Z̅ – (Y ∩ X)(Practice) Although the total number of bytes varies from computer to computer, memory sizes of millions and billions of bytes are common. In computer language, the letter M representsthe number 1,048,576, which is 2 raised to the 20th power, and G represents 1,073,741,824, which is 2 raised to the 30th power. Therefore, a memory size of 4 MB is really 4 times 1,048,576 (4,194,304 bytes), and a memory size of 2 GB is really 2 times 1,073,741,824 (2,147,483,648 bytes). Using this information, calculate the actual number of bytes in the following: a. A memory containing 512 MB b. A memory consisting of 512 MB words, where each word consists of 2 bytes c. A memory consisting of 512 MB words, where each word consists of 4 bytes d. A thumb drive that specifies 2 GB e. A disk that specifies 4 GB f. A disk that specifies 8 GB
- Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [A description or pseudocode (either is OK) of the algorithm, as well as a brief justification of its runtime.]Q2: There are three buckets size X, Y, M (1<=X<=Y<=M). All three buckets are initially empty. Using these three buckets, we can perform any number of the following two types of operations. We can fill the smallest bucket (of size X) completely to the top with X units of water and pour it into the size-M bucket, as long as this will not cause the size-M bucket to overflow. We can fill the medium bucket (of size Y) completely to the top with Y units of water and pour it into the size-M bucket, as long as this will not cause the size-M bucket to overflow. Although we may not be able to completely fill the size-M bucket, but we can still determine the maximum amount of milk we can possibly add to largest bucket. Sample input: 17 25 77 Sample output: 76 In this example, we fill the bucket of size 17 three times and then bucket of size 25 once, accumulating a total of 76 units of water. You could use additional test case to test your program: Input: 52 791 877 Output: 843 Input: 26…implement bitcount function Count the number of 1’s in x. you are onlyallowed to use the following eight operators:! ~ & ^ | + << >> “Max ops” field gives the maximumnumber of operators you are allowed to use to implement each function /** bitCount - returns count of number of 1's in x* Examples: bitCount(5) = 2, bitCount(7) = 3* Legal ops: ! ~ & ^ | + << >>* Max ops: 40*/int bitCount(int x) {return 2;}
- implement byteSwap(x,n,m) Swap the m and n byte of x /* * byteSwap - swaps the nth byte and the mth byte* Examples: byteSwap(0x12345678, 1, 3) = 0x56341278* byteSwap(0xDEADBEEF, 0, 2) = 0xDEEFBEAD* You may assume that 0 <= n <= 3, 0 <= m <= 3* Legal ops: ! ~ & ^ | + << >>* Max ops: 25*/ int byteSwap(int x, int n, int m) {return 2;}a. Translate with a three-address statement, the following expression: n = f((x+2), y) – 5; b. If A is an array of integers with width = 4; Translate with three-address statement, the following expression: x = a[i] + 2;Not pseudocode Suppose the economies of the world use a set of currencies C1, . . . , Cn; think of these as dollars, pounds, Bitcoin, etc. Your bank allows you to trade each currency Ci for any other currency Cj, and finds some way to charge you for this service. Suppose that for each ordered pair of currencies (Ci, Cj ), the bank charges a flat fee of fij > 0 dollars to exchange Ci for Cj (regardless of the quantity of currency being exchanged). Describe an algorithm which, given a starting currency Cs, a target currency Ct, and a list of fees fij for all i, j ∈ {1, . . . , n}, computes the cheapest way (that is, incurring the least in fees) to exchange all of our currency in Cs into currency Ct. Also, justify the its runtime. [We are expecting a description of the algorithm, as well as a brief justification of its runtime.]
- v = (3, 5)print(v)p, q = v[0], v[1]r = p + qif r % 2 == 0:p = p + r - 5q = q + r - pr = r + 1v = (p, q)print(v)else:p = p - 1q = q - 1if r % 3 != 0:v = (p, q)print(v)else:p, q = q, pv = (p, q)print(v)A = [15, 12, 13, 19, 14, 10, 16, 20, 9, 18, 8, 7]B = [19, 14, 8, 16, 20, 9, 18, 15, 12, 13, 7, 10]vN = 0for i in range(len (A)):vN = A[i]for j in range(len (B)):if B[j] ==vN:print ('A[',i,'] with B[',j,']') implementation this code with JUST one for loopGiven a positive integer, N, the ’3N+1’ sequence starting from N is defined as follows: If N is an even number, then divide N by two to get a new value for N. If N is an odd number, then multiply N by 3 and add 1 to get a new value for N. Continue to generate numbers in this way until N becomes equal to 1. For example, starting from N = 3 the complete ’3N+1’ sequence would be:3, 10, 5, 16, 8, 4, 2, 1 Do the following: Write a code in C++ to ask the user to enter a positive integer (N) in the main() function. Write a function sequence() that receives the integer value N and display the ‘3N+1’ sequence starting from the integer value that wasreceived (entered by the user). The function must also count and return the numbers that the sequence consists of. The returned value must be displayed from the main() function. Example input and output is given in the following image.