Prove that if G = (V, E) is a connected graph such that |E |V| – 1, then G is a tree. %3D

Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter10: Inequalities
Section10.4: Solving Combined Inequalities
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In lecture, we proved that any tree with n vertices must have n - 1 edges. Here, you
will prove the converse of this statement. From now on, you can use this converse in the same
way as you use statements from lecture.
Prove that if G = (V, E) is a connected graph such that E = |V| – 1, then G is a tree.
%3D
Transcribed Image Text:In lecture, we proved that any tree with n vertices must have n - 1 edges. Here, you will prove the converse of this statement. From now on, you can use this converse in the same way as you use statements from lecture. Prove that if G = (V, E) is a connected graph such that E = |V| – 1, then G is a tree. %3D
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