Prove that lim f(x)=36 if f(x)= x-6 x²x#6 5 x = 6 C For a function f(x) that is defined in an open interval about c, except possibly at c itself, the limit of f(x) as x approaches c is the number L if, for every number e > 0, there exists a corresponding number 8 >0 such that for all x, 0

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...
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Prove that lim f(x)=36 if f(x) =
x²x#6
5 x = 6
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For a function f(x) that is defined in an open interval about c, except possibly at c itself, the limit of f(x) as x approaches c is the number L if, for every number e > 0, there exists a corresponding
number 8>0 such that for all x, 0<x-c<8 implies that f(x)-L<e.
To prove the given limit statement, it is necessary to show that for all x, if 0<x-<8, then-36 <e.
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Transcribed Image Text:-k Prove that lim f(x)=36 if f(x) = x²x#6 5 x = 6 Ask my instructor ← For a function f(x) that is defined in an open interval about c, except possibly at c itself, the limit of f(x) as x approaches c is the number L if, for every number e > 0, there exists a corresponding number 8>0 such that for all x, 0<x-c<8 implies that f(x)-L<e. To prove the given limit statement, it is necessary to show that for all x, if 0<x-<8, then-36 <e. 6 M Clear all Check answer
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