Prove the converse of the Pythagorean theorem based on this Proof of the Pythagorean Theorem. A detailed proof is much appreciated

Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter8: Areas Of Polygons And Circles
Section8.5: More Area Relationships In The Circle
Problem 9E
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Prove the converse of the Pythagorean theorem based on this Proof of the Pythagorean Theorem. A detailed proof is much appreciated.

A New Proof of the Pythagorean Theorem
We refer the reader to the figure below. It follows that
bc
1
x b x c = 5
2
1
x a x A'D –→ A'D = -
2
ΔΑAC
a
The right triangles ABC and AEA' are similar. Hence,
A' E
c2
ΑΕ
b
Α'Α
АЕ
АЕ
A'E
ас
A'E =
b
АС
АВ
ВС
b
C
a
2bc
ΕΗ-Α'Η - A'E =
ас
a
b
The right triangles ABC and HEC are also similar. Thus
- CE = " × ( - ) = 26 -
a?
= 2b -
b
ЕН
СЕ
ЕН
СЕ
a
2bc
ас
AB
ВС
C
a
b
c2
+( 2b
a?
5)- a' = b° + c?.
AC = AE + EC → b :
D
E
C'
C
b
В
H
а
-Submitted by Nam Gu Heo, Korea National University of Education
http://dx.doi.org/10.4169/amer.math.monthly.122.5.451
MSC: Primary 51-01
May 2015]
A SIMPLE COMPUTATION OF 5(2k)
451
Transcribed Image Text:A New Proof of the Pythagorean Theorem We refer the reader to the figure below. It follows that bc 1 x b x c = 5 2 1 x a x A'D –→ A'D = - 2 ΔΑAC a The right triangles ABC and AEA' are similar. Hence, A' E c2 ΑΕ b Α'Α АЕ АЕ A'E ас A'E = b АС АВ ВС b C a 2bc ΕΗ-Α'Η - A'E = ас a b The right triangles ABC and HEC are also similar. Thus - CE = " × ( - ) = 26 - a? = 2b - b ЕН СЕ ЕН СЕ a 2bc ас AB ВС C a b c2 +( 2b a? 5)- a' = b° + c?. AC = AE + EC → b : D E C' C b В H а -Submitted by Nam Gu Heo, Korea National University of Education http://dx.doi.org/10.4169/amer.math.monthly.122.5.451 MSC: Primary 51-01 May 2015] A SIMPLE COMPUTATION OF 5(2k) 451
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