Prove the following switching relationships: (а) [А, В-1] 3 - (b) [A, [B, C]] + [B,[C,A]] + [C,[A, B]] = 0 (c) If [F, G] = 0 = [F=1,G] = [F, G-1] = [F=1,G¬1] = 0 (d) If [F,G] = 0=[F",G™] = 0, where m,n integers > 0 (e) If [F,H] = 0 & [G,H] = 0= [F G,H] = 0 В [А, В]В-1, where B-1B %3D BB-1 — 1 [F,G¬1] = [F=1, G-1] %D
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