Prove the lim(Sn) = -∞ case.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.1: Infinite Sequences And Summation Notation
Problem 74E
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Prove the lim(Sn) = - case.

10.7 Theorem.
Let (sn) be a sequence in R.
(i) If lim s, is defined [as a real number, +o or -0o), then
lim inf s, = lim s, = lim sup s,.
(ii) If liminf s, = limsup sn, then lim s, is defined and lim s, =
lim inf s, = limsup s,.
Proof
We use the notation un = inf{sn : n > N}, vN = sup{sn : n > N},
u = lim un = liminf s, and v = lim vN = lim sup s,.
(i) Suppose lim sn = +oo. Let M be a positive real number. Then
there is a positive integer N so that
n > N implies Sn > M.
Then uy = inf{s, :n > N} 2 M. It follows that m > N
implies um 2 M. In other words, the sequence (uN) satisfies
the condition defining lim uy = +o, i.e., lim inf sn = +o.
Likewise limsup sn = +0.
The case lim s, = -00 is handled in a similar manner.
Transcribed Image Text:10.7 Theorem. Let (sn) be a sequence in R. (i) If lim s, is defined [as a real number, +o or -0o), then lim inf s, = lim s, = lim sup s,. (ii) If liminf s, = limsup sn, then lim s, is defined and lim s, = lim inf s, = limsup s,. Proof We use the notation un = inf{sn : n > N}, vN = sup{sn : n > N}, u = lim un = liminf s, and v = lim vN = lim sup s,. (i) Suppose lim sn = +oo. Let M be a positive real number. Then there is a positive integer N so that n > N implies Sn > M. Then uy = inf{s, :n > N} 2 M. It follows that m > N implies um 2 M. In other words, the sequence (uN) satisfies the condition defining lim uy = +o, i.e., lim inf sn = +o. Likewise limsup sn = +0. The case lim s, = -00 is handled in a similar manner.
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