Prove the Product-to-Sum Identity sin A cos B = (1/2)[sin(A+B)+sin(A-B)] Start with the right-hand side: (1/2)[sin(A+B)+sin(A-B)] = %3D = (1/2)[(sinA)( B) + ( %3D A)( B) + (sinA)( B) - ( A)( B)] = %3D =(1/2)[2( A)( B) + 0] =sin COS -hand The last expression is the side of the original equation, hence, the proof is complete.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter6: The Trigonometric Functions
Section6.2: Trigonometric Functions Of Angles
Problem 64E
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Prove the Product-to-Sum ldentity
sin A cos B =
(1/2)[sin(A+B)+sin(A-B)]
Start with the right-hand side:
(1/2)[sin(A+B)+sin(A-B)] =
= (1/2)[(sinA)(
B) + (
A)(
B) + (sinA)(
B) - (
A)(
B)] =
=(1/2)[2(
A)(
B) + 0]
=sin
COS
-hand
The last expression is the
side of the original equation, hence, the proof
is complete.
Transcribed Image Text:Prove the Product-to-Sum ldentity sin A cos B = (1/2)[sin(A+B)+sin(A-B)] Start with the right-hand side: (1/2)[sin(A+B)+sin(A-B)] = = (1/2)[(sinA)( B) + ( A)( B) + (sinA)( B) - ( A)( B)] = =(1/2)[2( A)( B) + 0] =sin COS -hand The last expression is the side of the original equation, hence, the proof is complete.
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