Prove the Theorem: A real valued function on a closed, bounded interval is continuous iff its graph is closed and bounded.

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter3: Functions And Graphs
Section3.4: Definition Of Function
Problem 63E
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Prove the Theorem: A real valued function on a closed, bounded interval is continuous iff its graph is closed and bounded.

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If we assume that f(x) is unbounded at c , then bisecting the interval [a,b] would give us two intervals, over one of which, the function is unbounded(because if both of the subintervals were bounded, then the function would be unbounded over the entire interval [a,b] ).Advanced Math homework question answer, step 1, image 1

If we keep on bisecting each such subinterval, then we would end up with a series of nested intervals, converging on c . (This follows from the Nested Intervals Theorem. Though the Nested intervals theorem can return an empty intersection, this never happens if the intervals are closed.)

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