public static void print Pattern (int n) The main method that calls printPattern is given below: public static void main(String[] args) { // Create a Scanner Scanner input = new Scanner (System.in); // Prompt the user to enter the number of lines System.out.print ("Enter an even number between 2 to 20: "); int patternTarget input.nextInt (); = print Pattern (patternTarget); } Here are three sample outputs when the program is executed: Enter an even number between 2 to 20: 10 2 24 246 2468 2 4 6 8 10 Enter an even number between 2 to 20: 2 2 Enter an even number between 2 to 20: 20 2 24 246 2468 2 4 6 8 10 2 4 6 8 10 12 2 4 6 8 10 12 14 2 4 6 8 10 12 14 16 2 4 6 8 10 12 14 16 18 2 4 6 8 10 12 14 16 18 20
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Consider n as an even number and n is passted to the method as a parameter. Need help writing the program and the display result need to be as shown in the image attatched.
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- Complete the method definition to output the hours given minutes. Output for sample program: 3.5 import java.util.Scanner;public class HourToMinConv { public static void outputMinutesAsHours(double origMinutes) { /* Your solution goes here */ } public static void main (String [] args) { Scanner scnr = new Scanner(System.in); double minutes; minutes = scnr.nextDouble(); outputMinutesAsHours(minutes); // Will be run with 210.0, 3600.0, and 0.0. System.out.println("");}}Beginner Java import java.util.Arrays;import java.util.Scanner; Arrays and scanner required. Suppose that a Scanner object contains a bunch of tokens all on a single line separated by spaces. For example: 100.5 65 pizza 100 45.75 70 5.8 5 Also suppose that you have two integers n and m that are both positive. For example: n = 5 and m = 10 Write a static method: public static double partialSum(Scanner s, int n, int m) that takes a Scanner and two integers n and m as arguments and returns the sum of the integers read by the Scanner that are divisible by n and not divisible by m. In the above example, the integers divisible by 5 and not divisible by 10 are 65 and 5, so the result would be 70. If the Scanner is empty, or no tokens are valid integers, the result should be 0. You can assume the Scanner is not null. It is probably easiest to test your method by creating a Scanner with a String instead of System.in. The starter code for an example of how to do this is…import java.util.Scanner; public class DebugSix4 { public static void main(String[] args) { int high, low, count = 0; final int NUM = 5; Scanner input = new Scanner(System.in); System.out.print("This application displays " + NUM + " random numbers" + "\nbetween the low and high values you enter" + "\nEnter low value now... "); low = input.nextInt(); // Inserted the missing semicolon System.out.print("Enter high value... "); high = input.nextInt(); // Added the missing dot to the method call. while (low >= high) { // For proper input validation, changed "" to ">=" System.out.println("The number you entered for a high number, " + high + ", is not more than " + low); System.out.print("Enter a number higher than " + low + "... "); high =…
- **JAVA LANGUAGE** Beginner Level Suppose that a Scanner object contains a bunch of tokens all on a single line separated by spaces. For example: 100.5 65 pizza 100 45.75 70 5.8 5 Also suppose that you have two integers n and m that are both positive. For example: n = 5 and m = 10 Write a static method: public static double partialSum(Scanner s, int n, int m) that takes a Scanner and two integers n and m as arguments and returns the sum of the integers read by the Scanner that are divisible by n and not divisible by m. In the above example, the integers divisible by 5 and not divisible by 10 are 65 and 5, so the result would be 70. If the Scanner is empty, or no tokens are valid integers, the result should be 0. You can assume the Scanner is not null. It is probably easiest to test your method by creating a Scanner with a String instead of System.in. Tests to include in your main method: Test the above example with “100.5 65 pizza 100 45.75 70 5.8 5” as the…public class ArraySection { static void arraySection(int a[], int b[]) { int k = 0; int [] c = new int[a.length]; for(int i = 0; i < a.length; i++) { for(int j = 0; j < b.length; j++) if(a[i] == b[j]) c[k++] = a[i]; } for(int i = 0; i < k; i++) System.out.println(c[i]); System.out.println(); } public static void main(String[] args) { int a[] = { 1, 2, 3, 4, 5 }; int b[] = { 0, 2, 4,5 }; arraySection(a,b); }} Calculate the algorithm step number and algorithm time complexity of the above program?Complete method printPopcornTime(), with int parameter bagOunces, and void return type. If bagOunces is less than 2, print "Too small". If greater than 10, print "Too large". Otherwise, compute and print 6 * bagOunces followed by " seconds". End with a newline. Example output for ounces = 7: 42 seconds import java.util.Scanner; public class PopcornTimer {public static void printPopcornTime(int bagOunces) { /* Your solution goes here */ } public static void main (String [] args) {Scanner scnr = new Scanner(System.in);int userOunces; userOunces = scnr.nextInt();printPopcornTime(userOunces);}}
- Need help with following Java method: import java.util.Scanner; import java.lang.Math; public class CosineFromScratch { /* The following code demonstrates how to estimate the cosine of a number. Your assignment is to migrate the calculation of the cosine into a new static method named cosine. The method should take one double input and return one double output. Make sure to call the method from main and set the variable estimate equal to the returned value. */ public static void main(String[] args) { Scanner input = new Scanner(System.in); System.out.print("\nGive me a number: "); double x = input.nextDouble(); //Trying to find cosine of this number double correct_cos = Math.cos(x); //START HERE: The following code goes into //the method. //Source for the following: //https://austinhenley.com/blog/cosine.html double num_terms = 10; int div = (int)(x / Math.PI); x = x - (div * Math.PI); int sign = -1; double estimate = 1.0;…**JAVA LANGUAGE** beginner level import java. util.Arrays;import java.util.Scanner; Suppose that a Scanner object contains a bunch of tokens all on a single line separated by spaces. For example: 100.5 30.4 pizza 56.8 1000.3 8.2 Also suppose that you have a particular item that you know the price of. Let’s use the following example: Kindle: 99.99 Write a static method: public static double priceIsRight(Scanner s, double price) that takes a Scanner and an item price as parameters and returns the bid that is closest to the item price but not greater than the item price. If all bids are greater than the price, return 0.0. If there are no bids (Scanner is empty) return 0.0. You can assume the Scanner is not null. In the above example. 56.8 should be returned, since it is the number that is closest to 99.99 but not over 99.99. Notice that there may be some invalid tokens in the Scanner's input. The above example has pizza as one of its tokens, which is clearly not a valid bid. Your…1-Write the pseudocode for this method 2-Flowchart for this method public static void bucketSort(int[] arr) { int max_value = 0; for (int i = 0; i < arr.length; i++) if (arr[i] > max_value) max_value = arr[i]; int[] bucket = new int[max_value + 1]; for (int i= 0; i
- Write a recursive method called digitCount() that takes a positive integer as a parameter and returns the number of digits in the integer. Hint: The number of digits increases by 1 whenever the input number is divided by 10. Use Java. Ex: If the input is: 345 the method digitCount() returns and the program outputs: 3 Ex: If the input is: 0 the method digitCount() returns and the program outputs: 1 import java.util.Scanner; public class LabProgram {/* TODO: Write recursive digitCount() method here. */public static void main(String[] args) {Scanner scnr = new Scanner(System.in);int num, digits;num = scnr.nextInt();digits = digitCount(num);System.out.println(digits);}}public static void main(String [] args){ int num1 = 5, num2 = 10; swap(num1, num2); System.out.println(“num1 is ”+ num1); System.out.println(“num2 is ”+num2);} public static void swap(int a, int b){ temp = a; a = b; b = temp;} What is the output of the main method?A monochrome screen is stored as a single array of bytes, allowing eight consecutivepixels to be stored in one byte. The screen has width w, where w is divisible by 8 (that is, no byte willbe split across rows). The height of the screen, of course, can be derived from the length of the arrayand the width. Implement a function that draws a horizontal line from ( xl, y) to ( x2, y).The method signature should look something like:drawline(byte[] screen, int width, int xl, int x2, int y)