PYTHON Time Complexity (Big-O) consider a modification to baz(a) called bazzab(a) below: def bazzab(a): def baz(a): if len(a) < 1: return [""] t = [] for i in range(len(a)): for j in baz(a[:i] + a[i+1:]): t.append(a[i] + j) Is it possible to have another algorithm that is functionally the same as bazzab(a) but has a better time complexity? If no, briefly explain why. If yes, provide the fastest solution that you can think of and justify its time complexity, return t the better the time complexity of your solution, the higher your score. p = set() for s in baz(a): if s == s[::-1]: p.add(s) return p
PYTHON Time Complexity (Big-O) consider a modification to baz(a) called bazzab(a) below: def bazzab(a): def baz(a): if len(a) < 1: return [""] t = [] for i in range(len(a)): for j in baz(a[:i] + a[i+1:]): t.append(a[i] + j) Is it possible to have another algorithm that is functionally the same as bazzab(a) but has a better time complexity? If no, briefly explain why. If yes, provide the fastest solution that you can think of and justify its time complexity, return t the better the time complexity of your solution, the higher your score. p = set() for s in baz(a): if s == s[::-1]: p.add(s) return p
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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B. Python
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![ΡΥTHOΝ
Time Complexity (Big-O)
consider a modification to baz(a) called bazzab(a) below:
def bazzab(a):
def baz(a):
if len(a) < 1:
return [""]
t = []
for i in range(len(a)):
for j in baz(a[:i] + a[i+1:]):
t.append (a[i] + j)
Is it possible to have another algorithm that is functionally the same
as bazzab(a) but has a better time complexity? If no, briefly explain why.
If yes, provide the fastest solution that you can think of and justify its time complexity,
return t
the better the time complexity of your solution, the higher your score.
p = set()
for s in baz(a):
if s == s[::-1]:
p.add(s)
return p](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F30ffc4d3-8c1a-411e-990c-595fde6a9f46%2Ff148a807-a556-42cf-ac94-2bebd75d71f5%2F1a42w4c_processed.png&w=3840&q=75)
Transcribed Image Text:ΡΥTHOΝ
Time Complexity (Big-O)
consider a modification to baz(a) called bazzab(a) below:
def bazzab(a):
def baz(a):
if len(a) < 1:
return [""]
t = []
for i in range(len(a)):
for j in baz(a[:i] + a[i+1:]):
t.append (a[i] + j)
Is it possible to have another algorithm that is functionally the same
as bazzab(a) but has a better time complexity? If no, briefly explain why.
If yes, provide the fastest solution that you can think of and justify its time complexity,
return t
the better the time complexity of your solution, the higher your score.
p = set()
for s in baz(a):
if s == s[::-1]:
p.add(s)
return p
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