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- The modulus of elasticity of mild steel is equal to .. .? .... .. a. 2 x 10ʻN/m? a. 2 x 10'N/m 2 b. 2 x 10° N/m 4 c. 2 x 10 N/mm 5 d. 2 x 10 N/mm CheckQ2/Show the mechanical properties changes during tensile test of a metal specimen. Write the mathematical relationships. 443X2.3-7 A steel bar 2.4 m long has a circular cross section of diameter d, = 20 mm over one-half of its length and diam- eter d, = 12 mm over the other half (see figure part a). The modulus of elasticity is E = 205 GPa. (a) How much will the bar elongate under a tensile %3D %3D load P = 22 kN?
- An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm A = 400mm? A- 200mm 40KN 10KN 20KN 1.5m 2.5m 2.0m Determine the change in length of steel rod having a length of 800mm and a diameter of 6.5mm. The rod is subjected to a force P equal to 110KN. Young's Modulus is 200GPA Compute normal strain of the rodFind the lightest S-shape for the beam shown if the working stress in bending is 175 MPa. What is the maximum bending stress in the beam selected? 50 kN/m 4 m -2.4 m· -x X- TABLE B-3 Properties of I-Beam Sections (S-Shapes): SI Units Flange Axis Y-Y Web X-X spxy Mass Area Width ıdə (wu) Thickness thickness Pl1 = S (10³ mm³) yli^ = 4 (10° mm*) (u) 27.7 27.7 22.1 Designation (10° mm*) (ww) 20.3 (ww) 38.9 („ww) (ww) (ww) 081 158 006 77 622 622 204 1 320 1 220 081 x 019S 4 230 240 34.5 338 × 158 x 149 x 134 007 184 15.7 3930 3 260 247 O'ZE 19.7 320 001 07 6'6E 32.3 006 81 00 I 15 200 149 6'81 15.9 166 937 677 234 019 215 134 181 22.1 090 € 2870 019 18.6 205 33.0 611 22.1 12.7 874 241 17.5 197 61I x 34.0 019 S510 × 143 143 18 200 16300 14 200 12 500 91S 91S 183 23.4 23.4 20.2 20.3 16.8 S69 653 2 700 20.8 228 x 128 x 112 × 98.2 128 112 33.8 34.5 29.5 179 961 2 540 007 194 19.4 80s 508 216 152 162 16.1 533 001 7 1950 12.3 98.2 20.2 12.8 495 6SI 11.4 144 30.2 661 S460 × 104 104 13 200 457 6SI…(40 How A Rismatic steel bar of a Square cro ss section (looxlo0)mm is loaoled by Compressive force P= 1300 K, the bar has length 2.5 m, Eg=200GPay V=0.3,determine the shortening 8, the increase in the dimensions of cross Section, the change in Volume DV of the bar? loomm loomm
- An aluminum rod is rigidly attached between a steel rod and a bronze as shown. Axial loads are applied at the positions indicated. Find the stress of each rod in MPa. Steel Aluminum Bronze A- 500mm? A = 400mm? A - 200mm 40KN 10KN 20KN 2.5m 2.0m 1.5mThe cross-sectional area of an aluminum bar is 170 mm?. It carries an axial loads at the positions as shown in the figure. Compute the total deformation of the bar if E = 80 Gpa. Assume the bar is suitably braced to prevent buckling. Add "9" in the loads only. Example: 40+9=49, 18+9=27, 42+9=51, 20+9=29 Area = 170mm' 2 40KN 18KN 20KN 42KN 1.0m 1.80m 0.70mPROBLEM 01: Hollow bar length is 1.40m long and tube length is three-fourth as long as the bar. Torque T=1100N.m acts at the free end of the bar. Both the bar and tube are made of an aluminum alloy with shear modulus of w ww elasticity G=27GN/m². Given that dl=35mm, d2=45mm, d3=60mm, d4=70mm. Determine the following: a. Maximum shear stress in both the bar and tube b. Angle of twist at the end A of the bar. (In degrees) Tube Fixed plate End plate Tube d3 d1 d2 d4 Bar Cross-section of the bar and tube
- A compressive load P is transmitted througha rigid plate to three magnesium-alloy bars that areidentical except that initially the middle bar is slightlyshorter than the other bars (see figure). The dimensionsand properties of the assembly are as follows:length L = 1.0 m, cross-sectional area of each barA = 3000mm2, modulus of elasticity E = 45 GPa,and the gap s = 1.0 mm.(a) Calculate the load P1 required to close the gap.(b) Calculate the downward displacement d of therigid plate when P = 400 kN.(c) Calculate the total strain energy U of the threebars when P = 400 kN.(d) Explain why the strain energy U is not equal toPδ / 2. Hint: Draw a load-displacement diagram.PROBLEMS: 1. The bolt connection shows 8-22mm diameter bolts in a bolt hole diameter of 25 mm and spaced according to the following: Sı = 40mm T = 16mm S2 = 80mm S3 = 50mm S4 = 100mm te = 12mm Determine the force T if the allowable tensile stress is 200 MPa, the allowable bolt shear stress is 120MPa and the allowable plate bearing stress is 120 MPa. 2. A long retaining wall is braced by wood shores set at ang angle of 30° and supported by concrete thrust blocks as shown. The shores are evenly spaced, 3m apart. For analysis purposes, the wall and shores are idealized on the second image. Note that the base of the wall and both ends of the shores are assumed to be pinned. The pressure of the soil against the wall I assumed to be triangularly distributed, and the resultant force acting on a 3-meter length of the wall is F= 190KN. If each shore has a 150mmx150mm square cross section, what is the compressive stress in the shores? Retaining wall Soil Concrete Shore thrust block 30 30 1,5 m…The compound bar ABCD has a uniform cross-sectional area of 0.25 in.² When the axial force P is applied, the length of the bar is reduced by 0.018 in. Determine the magnitude of the force P. The moduli of elasticity are 29 x 10^6 psi for steel and 10 x 10^6 psi for aluminum. Please include the details. Thank you.