Q) Reorder the following code to speed up. How many number of clock cycles can be saved with this reordering? MOVE.W D1,D0 ADD.W D0,D3 MULU D3,D1 LEA (A4),A6 MOVE.W #$3400,D2 ADDA.W D7,A2 MOVE.W #$F6AA,D4
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Q) Reorder the following code to speed up. How many number of clock cycles can be saved with this reordering? MOVE.W D1,D0
ADD.W D0,D3
MULU D3,D1
LEA (A4),A6
MOVE.W #$3400,D2
ADDA.W D7,A2
MOVE.W #$F6AA,D4
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- DO NOT COPY FROM OTHER WEBSITES For the following code segments: -identify the statements that are “mice”. -identify the Big-O run-time (show how you arrived at the answer )analyze each program and figure out what is wrong with the memory management in the code and how to fix the code. #include <unistd.h>#include <stdio.h>#include <stdlib.h>#include <assert.h> // Hint: If you run this program repeatedly, with ever-larger numbers as input,// eventually something (slightly) unexpected should happen.intmain(int argc, char *argv[]){if (argc != 2) { fprintf(stderr, "usage: broken2 <value>\n"); exit(1); } int size = atoi(argv[1]);int *p;p = malloc(size*sizeof(int));for (int i = 0 ; i < size; i++) {p[i] = i;}int *q;q = malloc(sizeof(p));for (int i = 0 ; i < size; i++) {q[i] = p[i];} free(p);free(q);return 0;}Complete the following sentences by filling the right word To check if two string variables string1 and string2 refer to the same memory address we use the command ………
- Hello I need help with the following question, I have provided my work that I have done and an example of completed work from the class. This is the question I need help with. A system currently accessing 3.8 G bytes of RAM and 10 M bytes of ROM. Compute the number of address lines required to access the designated storage. For a given # of lines how many more storage space is accessible? Currently out of 3.8 G, 3 G is used by the system programs, .4 G by an application. Can we expand the memory by another 890 M to support a new application? show total storage use and available. Show all your work.Question 1 options: Assume the memory address of variable 'a' is 0x2ac4281c. What will be the output? int a = 7; int *c = &a; c= c+3; printf("%x\n",c); ______________#include <stdio.h> #include <stdint.h> #include "qutyio.h" // Ex E3.0 // // In this week's tutorial we used some functions from a library // "qutyio.h" and from the <stdio.h> library to output data via // the serial interface. This can be a useful tool for debugging // your programme. To use the serial interface you first need to // initialise the required hardware by calling "serial_init()"; // this only needs to be done once at the beginning of your // programme. After this, you can use the function printf() from // <stdio.h> to output formatted strings via the serial interface. // // You will need to use printf() in few different ways in this // extension exercise: // // printf("foo") - prints the word 'foo' to the serial output. // printf("bar") - prints the word 'bar' to the serial output. // printf(" ") - prints a space to the serial output. // printf("%02X", x) - prints the 8-bit integer 'x' to the // serial output, formatted as two…
- Problem 1: Suppose you were given the following number to find its power and display the result: 5 4 1.53 505 So, how do you solve this problem? Filename: power.javaWhat is the importance of including '0' in saving the data to the RAM?You are required to make changes in the below programs and introduce the use of compaction where required. #include<stdio.h> #include<conio.h> main() { int ms, bs, nob, ef,n, mp[10],tif=0; int i,p=0; clrscr(); printf("Enter the total memory available (in Bytes) -- "); scanf("%d",&ms); printf("Enter the block size (in Bytes) -- "); scanf("%d", &bs); nob=ms/bs; ef=ms - nob*bs; printf("\nEnter the number of processes -- "); scanf("%d",&n); for(i=0;i<n;i++) { printf("Enter memory required for process %d (in Bytes)-- ",i+1); scanf("%d",&mp[i]); } printf("\nNo. of Blocks available in memory -- %d",nob); printf("\n\nPROCESS\tMEMORY REQUIRED\t ALLOCATED\tINTERNAL FRAGMENTATION"); for(i=0;i<n && p<nob;i++) { printf("\n %d\t\t%d",i+1,mp[i]); if(mp[i] > bs) printf("\t\tNO\t\t---"); else { printf("\t\tYES\t%d",bs-mp[i]);tif = tif + bs-mp[i]; p++; } } if(i<n) printf("\nMemory is Full, Remaining Processes cannot be accomodated"); printf("\n\nTotal…
- Note:- Study this program and follow the given instruction and type execute the code and also give output for this java program as soon as possible. Modify example six to read file tooutfile2.txt compute and display the total. Then write the total to a file named tooutfile2A.txt exampleSix This program creates file tooutfile2.txt and stores 10 integers in it Please verify that the file was created along with the content package pwriter2; import java.util.Scanner; import java.io.*; public class Pwriter2 { public static void main(String[] args) throws IOException { PrintWriter tofile2 = new PrintWriter( "tooutfile2.txt" ); int i = 0; while (i < 10){ tofile2.println( i ); i = i + 1; } tofile2.close(); } }Write an ARM assembly program to convert temperatures from Celsius to Fahrenheit or from Fahrenheit to Celsius. Here are the two formulas for your reference. Use variable to read and store values, you can initialize any integer value into the variables (Do not expect decimal results we are only doing integer operations). C = 5 × (F − 32) / 9 F = (9 × C / 5) + 32 Name the file TempConvert.s add the below commenting statements in the program ;Name: ;Date: ;Give which expression you useWrite an ARM assembly program to convert temperatures from Celsius to Fahrenheit or from Fahrenheit to Celsius. Here are the two formulas for your reference. Use variable to read and store values, you can initialize any integer value into the variables (Do not expect decimal results we are only doing integer operations). C = 5 × (F − 32) / 9 F = (9 × C / 5) + 32 Name the file TempConvert.s add the below commenting statements in the program ;Name: ;Date: ;Give which expression you use Please use LDR/STR