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- Think about the following example: A computer program builds and modifies a linked list like follows:Normally, the program would keep tabs on two unique nodes, which are as follows: An explanation of how to use the null reference in the linked list's node in two common circumstancesIn c++ , write a program to create a structure of a node, create a class Linked List. Implement all operations of a linked list as member function of this class. • create_node(int); • insert_begin(); • insert_pos(); • insert_last(); • delete_pos(); • sort(); • search(); • update(); • reverse(); • display(); ( Drop coding in words with screenshot of output as well )Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a=0; while(curNode->getItem()<7){ a+=curNode->getItem(); curNode=curNode->getNext(); } A. 13 B. 5 C. 8 D. 21
- Question : Write a program to remove duplicates from a doubly linked list. e.g (1,2,3,4,5,2) (you will remove the 2nd duplicate) and then swap two data items in a doubly linked list. swap address of node 2 with node 4.Assume a linked list contains following integers: 4, 2, 6, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a; curNode=curNode->getNext(); head->setNext(curNode); head=head->getNext(); a=head->getItem(); A.2 B.4 C.6 D.15Assume a linked list contains following integers: 2, 2, 4, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode; curNode=new Node<int>(10,head); head=curNode; int a; while(curNode!=NULL){ a+=curNode->getItem(); curNode=curNode->getNext(); } A.49 B.39 C.7 D.15
- C++ question 1.) Write an iterative routine that will take a string, go through each character of the string and enqueue the character if it is a punctuation (.,?!), else toss the character. When end of string is reached, then dequeue the characters, count how many punctuations are there, then print the count. 2.) Write a routine that would receive a pointer to the top of the linked list that has an integer for each node. Change all odd integers to even by adding one. But count the numbers you changed and print the count.Assume a linked list contains following integers: 7, 2, 9, 5, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; int a; while(curNode->getNext()!=NULL){ { curNode=curNode->getNext(); } a=curNode->getItem(); A. 15 B. 7 C. 49 D. 3Assume a linked list contains following integers: 7, 2, x, 5, 8, x, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; curNode=curNode->getNext(); curNode=curNode->getNext(); int a; a=curNode->getItem(); 1. x 2. 2 3. 7 4. x+9
- python programming Write a function that will insert a new value into the middle of a Linked List. INPUT: The head of the Linked List, the value to insert OUTPUT: Nothing is output RETURNED: Nothing is returnedAssume a linked list contains following integers: 5, 2, 4, 6, 8, 3, 15 and the pointer head is pointing to the first node of the list. What will be the value of variable a after the following statements are executed: Node<int> *curNode=head; curNode=curNode->getNext(); curNode=curNode->getNext(); int a=curNode->getItem()<<endl; Group of answer choices A.4 B.2 C.5 D.6Part2: LinkedList implementation 1. Create a linked list of type String Not Object and name it as StudentName. 2. Add the following values to linked list above Jack Omar Jason. 3. Use addFirst to add the student Mary. 4. Use addLast to add the student Emily. 5. Print linked list using System.out.println(). 6. Print the size of the linked list. 7. Use removeLast. 8. Print the linked list using for loop for (String anobject: StudentName){…..} 9. Print the linked list using Iterator class. 10. Does linked list hava capacity function? 11. Create another linked list of type String Not Object and name it as TransferStudent. 12. Add the following values to TransferStudent linked list Sara Walter. 13. Add the content of linked list TransferStudent to the end of the linked list StudentName 14. Print StudentName. 15. Print TransferStudent. 16. What is the shortcoming of using Linked List?