Q.4. Give a reason for the following facts: 1- Ceramics fail after only about 0.1% strain under tensile test. 2- Porosity is an inherent defects in ceramics. 3- Ceramics carbides consider ideal choice for ceramic abrasives. 4- Orthoclase has the advantage over other types of feldspar.
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- Given your understanding of what initiates and controls failure in materials, which of the following will increase the failure strength or lifetime of a test piece or component and why? a. Decreasing the difference between the maximum and minimum stress values, as this effects the stress concentration factor b. Decreasing the temperature below the brittle-ductile transition temperature, to make it harder C. Polishing to reduce surface defects Od. Increasing its volume, to give a larger cross sectional area Oe. Increasing the grain size so there are less grain boundaries to initiate failureA specimen of alloy having the following engineering stresses produces the corresponding plastic engineering strains, prior to necking: Engineering Stress (MPa) Engineering Strain 353.7 0.0357 371.3 0.0436Which of the following is correct when we increase the volume fraction porosity of a ceramic material? both the flexural strength and modulus of elasticity decreases flexural strength decreases, while modulus of elasticity increases flexural strength increases, while modulus of elasticity decreases both the flexural strength and modulus of elasticity increases
- Compare the difference in hardenability of plain carbon steels given below. Hardenability is the strengthening of steels by the process of quenching + tempering. Chemical compositions ( wt % ) C Mn P S Fe Steel 1 0.2 0.45 0.04 0.05 99.26 Steel 2 0.4 0.75 0.04 0.05 98.76 Steel 3 0.6 0.75 0.04 0.05 98.56Which one of the following processes causes a dramatic increase in the hardness of a steel part? A) quenching B) tempering (c) normalizing D full annealingA batch of casted mild steel has a modulus of elasticity of 200 GPa and a yield strength of 250 MPa. Calculate for its modulus of resilience. After cold working the steel, the yield strength increases to 310 MPa. Calculate for the percent reduction in the average grain diameter given σo = 70 MPa and k = 0.74.
- After an inspection it is found that a structural ceramic part has no flaws greater than 100 micrometers in size, calculate the maximum service stress (in MPa) available with SiC. Assume that Y= 1Material A is known as a high strength material and Material B has high toughness. Explain the difference between properties of Materials A and B.Why Ceramics are stronger in compression than in tension
- Q) Which one is NOT a result of having flaws in ceramics? Low tensile strength Stress concentration Plasticity Brittle failureThe following information about the o-e curve is given for a steel alloy. E = 0.001527 at o = 300 MPa and ɛ = 0.003054 for o = 600 MPa. (a) Draw the stress-strain diagram and calculate the E for this alloy.i need quickly please please please Which of these cast iron would allow the greatest amount of plastic deformation before fracture . Nodular cast iron Grey cast iron White cast iron None of them can be worked. If the diameter of steel specimen stretched by tension load is doubled , then it’s tensile strength will be Halved Remain unaffected Doubled Become four times Temperature is proportional with Percent of elongation Tensile strength Modulus of elasticity All above The tensile strength of a steel specimen that have a 182 HB , equals to 490 MPa 910 MPa 627 MPa Not given…