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Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm³/mol and P is in atm for Pressure between 0 and 1000 atm and Стз .K) `mol (əv = 0.0045 + 1.4 × 10-6P Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.

Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 10ª P + 4.6 X 108 P², where V is in cm³/mol and P is in atm for Pressure between 0 and 1000 atm and Стз .K) `mol (əv = 0.0045 + 1.4 × 10-6P Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
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Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 104 P + 4.6 X 10º P², where V is in cm/mol and P is in atm for Pressure between 0 and 1000 atm and əv Ст3 7.K) = 0.0045 + 1.4 × 10-6P mol Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
Transcribed Image Text:Q.5 At 25°C the molar volume of water V is given by: V = 18.066 – 7.15 X 104 P + 4.6 X 10º P², where V is in cm/mol and P is in atm for Pressure between 0 and 1000 atm and əv Ст3 7.K) = 0.0045 + 1.4 × 10-6P mol Determine the work necessary at 25 °C to compress 1 mol of water from 1 atm to 1000 atm and the change in its internal energy.
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