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- New Jave code must be entered inbetween grey blocks of code as seen in photoC programming: Fill Out the TODO'S IN THE PROGRAM : #include <stdlib.h> // EXIT_ codes#include <stdbool.h> // bool#include <stdio.h> // printf, scanf#include <string.h> // strlen, strcmp#include "udp.h" // udp library#define CLIENT_LISTENER_PORT 4097#define SERVER_LISTENER_PORT 4098#define MAX_CHARS_PER_MESSAGE 80//-----------------------------------------------------------------------------// Main//-----------------------------------------------------------------------------int main(int argc, char* argv[]){char *remoteIp;char *mode;int remotePort;char str[MAX_CHARS_PER_MESSAGE+1];bool quit = false;bool sendMode;// Verify arguments are goodbool goodArguments = (argc == 3);if (goodArguments){remoteIp = argv[1];mode = argv[2];goodArguments = (strcmp(mode, "server") == 0) || (strcmp(mode, "client") ==0);}if (!goodArguments){printf("usage: chat IPV4_ADDRESS MODE\n");printf(" where:\n");printf(" IPV4_ADDRESS is address of the remote machine\n");printf(" MODE is…given ASCIIOFSET .FILL x0030 NegASCIIOFSET .FILL xFFD0 ASCIINewline .FILL x000d ; Newline ascii code ASCIISpace .FILL x0020 ; Space ascii code ASCIIComma .FILL x002C ; Comma ascii code Use LC-3 I/O device to print number, commas, and spaces in printCommaSpace subroutine, also check code to see if it follows instructions and modify accordingly
- A = {0,2,4,6} B = {{0},{2}, {4},{6}} C = A ∪ Ø D= A ∪ {Ø} E= { n ∈ ℕ | n² ∈ ℕ } F= { n² ∈ ℕ | n ∈ ℕ } Which are the following are true? 1. A ⊆ E, B ⊆ E, A ⊆ F, B ⊆ F, E ⊆ F, F ⊆ E. 2. O ∈ A, 0 ∈ B, {0} ∈ A, {0} ∈ B.15. When data and acknowledgement are sent in the same frame, this is called as a. Piggy packing b. Piggy backing c. Back packing d. Good packingCurrently in Brazil (year 2021), landline numbers are 8 digits long, and cell phone numbers, 9 digits. This number is regional, so to complete an identification of the user in Brazil that a number corresponds, it is also important the area code (DDD), composed of 2 digits. It's common people provide their phone number either including the area code, or not including it. Just following these size rules, some examples of phone numbers valid in Brazil: 2191231616511323161657191231616532323161632316165912316165 Make a function that receives as input a string containing a sequence of digits, which is supposed to it matches the phone number entered by a user (assume this string it only has digits). Your function must identify if the phone number is a valid number in Brazil (what means, if it fits one of the acceptable standards). If so, your function should return a tuple with two strings, the first containing exactly two digits that match the DDD (or empty string, if the area code was not…
- This is the updated code that I have: .data .globl main .textmain: # compute the next state of the LFSR for each input state li $a0, 0x00000001 jal lfsr_next_state move $t0, $v0 li $a0, 0xdeadbeef jal lfsr_next_state move $t1, $v0 li $a0, 0x200214c8 jal lfsr_next_state move $t2, $v0 li $a0, 0x00000000 jal lfsr_next_state move $t3, $v0 # print the output states move $a0, $t0 li $v0, 1 syscall move $a0, $t1 li $v0, 1 syscall move $a0, $t2 li $v0, 1 syscall move $a0, $t3 li $v0, 1 syscall # exit the program li $v0, 10 syscall # Function to compute the next state of an LFSR# Input parameter: $a0 = current state# Output: $v0 = next statelfsr_next_state: # Initialize upper mask with 0x7fff and lower mask with 0x8000 lui $t0, 0x7fff ori $t0, $t0,…subject: CSCI 4970: SPT Intro to 3D Video games 1. Answer the following questions with true of false a. T/F you can adjust the range for a point light b. T/F the following function moves a gaming object: transform.translate(1,2,3) c. T/F spot lights are a kind of light source where all the light rays originate from a single point and project out in all directions, like a light bulb in the real world. the light is brighter up close because the light rays are bunched up09.Code: There are two A, B players playing the game. Player A is angry with him, and player B is angry with him. Both s and t include only small English letters and are of equal length. A makes the first move, then B, then A, and so on. Before the start of the game, players are familiar with the content of both the letter s and t characters. These players form one rope during the game. Initially, the character unit w is empty. In each move, the player removes any single letter from the alphabetical order in order and adds this letter any (any position) to the letter w you can add a character to any index. Please refer to the Definitions for more specifications). If in any stage of the game, the character unit w is more than 1 length and is a palindrome, the player who made the last move wins. If even after the end of the game (i.e., when both s and t are empty strings), no one can make a unit of characters w a palindrome, and then player B wins. Given the unit of the letters s, and t,…
- There should be two files or codes for this solution: the distance code and the second code fallingdistanceNUMBER 7 Code the following in DEV C++ Rules: 1. Kindly code it in a proper way 2. The symbols and values are posted here: r1 = outer radiusr2 = inner radiusC1 = outer circumferenceC2 = inner circumferenceA1 = area of circle of r1, area within outer circleA2 = area of circle of r2, area within inner circleA0 = shaded area, outer area minus inner areaA0 = A1 - A2π = pi = 3.1415926535898√ = square root 3. Example of the code is this Annalus Calculator https://www.calculatorsoup.com/calculators/geometry-plane/annulus.php 4.. Please don't reject CODE THE FOLLOWING (SEE ATTACHED PHOTO):Code the following in DEV C++ Rules: 1. Kindly code it in a proper way 2. The symbols and values are posted here: r1 = outer radiusr2 = inner radiusC1 = outer circumferenceC2 = inner circumferenceA1 = area of circle of r1, area within outer circleA2 = area of circle of r2, area within inner circleA0 = shaded area, outer area minus inner areaA0 = A1 - A2π = pi = 3.1415926535898√ = square root 3. Please don't reject CODE THE FOLLOWING: Calculate and display: outer circumference, inner circumference, area enclosed by the outer circle, area enclosed by the inner circle, area of the shaded region Given: outer radius r1 inner radius r2. Formula to be used: Outer circumference = C1=2πr1, inner circumstance = C2=2πr2, enclosed by the outer circle = A1=πr12, the area enclosed by the inner circle= A2=πr22, rea of the shaded region= A0=A1-A2