Q1) A- Write an equations for the normal lines on the circle tangent at (x= 1) with (r-10),c(0,0),

Q: Find the condition that the line ax+by=1 may be a normal to the curve an-1y=xn

A: To find the condition of line ax + by = 1 which is normal to the curve a^(n-1) y = x^n

Q: 7. For the curve y = x2 + x, at what point does the normal line at (0,0) intersect the tangent line…

A: Find the slope of the tangent at (0,0): m=dydx=2x+1=20+1=1

Q: Find the normal to the curve y = 1 - x at the point (3, -8).

A:

Q: Find an equation of the normal line to the curve  y = sqrt(x)  that is parallel to the line  4x +…

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Q: Find an equation of the normal line to the curve  y = x  that is parallel to the line  4x + y = 1.

A:

Q: find the equation of the normal line to the curve y=x^3 + 3/x at (1,4)

A: Solution ) Normal line is perpendicular to the tangent line  So first find slope of the tangent line…

Q: Find an equation of the normal line to the curve y = vx-3 which is parallel to the line 6x + 3y-4 0.

A:

Q: (A) Find the equation of tangent and normal to the curve 2x2 + y = 9 at (-2, –1).

A: To find the equation of tangent and equation of normal at the given curve .

Q: The Normal to the curve 2x² – y² = 1 at the point (1,1)

A:

Q: y = 4x3 – 12x² – 16x at x = 1

A: Equation of line at point (a, b) and slope m is : (y - b) = m*(x - a)

Q: Find the equation of the normal line to the curve x3+y2+2x−6=0 at the point (−1,3).

A:

Q: Find the equations of the tangent and the normal at the point indicated. y = 2 + 4x - x2 at x= -1

A: Given : The equation of the curve is y=2+4x-x2 at x=-1 Let m= the slope of the tangent line at x==-1…

Q: what is the equation of the normal line to the curve x^2+y^2-6x-2y=0 at (2,4)?

A:

Q: Find the condition that the line ax+by =1 may be normal to the curve an-1y =xn

A: Given thatan-1y =xn Solution is as follows

Q: Find the equations of the tangent and the normal of y = 3x2-2x+1 at point (1,2).

A:

Q: y = x3 + 6x² + 9x – 2 at x = 0 -

A: topic - equation of tangent and normal Line to the curve

Q: Find an equation of normal line to the curve y = Vx that is parallel to the line 2x+y = 4.

A:

Q: Find the equation of the line tangent to the graph a the given point using definition and verify by…

A:

Q: 2. What is the slope of the line tangent to the curve 8x³ – y² = 4 at the point (1,-2)? 3. What is…

A: Since first subparts question statement missed. Answer 2 and 3

Q: Find an equation of the normal line to the curve of y = Vx that is parallel to the line 6x + y = 1.…

A: Given that: The curve y = x parallel to the line 6x + y = 1 To find: The equation of normal line to…

Q: What is the normal line to the curve 9x2 +4y2 = 36 at (0,3)? (А) у-2-0 B X+1=0 Cy-axis D X- axis

A: We need to find the normal equation of the at (0,3).

Q: b) Find equation of line passing the point ( 4, -1) and normal to 3y+ x=1. ||

A:

Q: Find the equation of the tangent line and the normal line of the curves at given point 1. 4x? + 9x?…

A: The given equation,     4x2+9x2=25, 2,-1

Q: 20. Does the line that is normal to the curve y = x² + 2x - 3 at the point (1, 0) intersect the…

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Q: Determine the equation of the normal line to the curve y= 2 − (1/3) x2 that is parallel to the line…

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Q: Find the equation of the tangent and normal line using the stipulated conditions   1.) y = x2 - 5x…

A: Given the equation is y = x2 - 5x The point of intersection line y=6 The equation of the tangent is…

Q: The equation of the line tangent to the curve at (−1,4)is x+y=3. What is the slope of the normal…

A: Product of slopes of two perpendicular lines is -1.

Q: y = x3 – 3x2 – 9x + 5 at x = 1

A:

Q: Find the condition that the line ax+by=1vmay be a normal to the curve an-1 y=xn

A: follow next step

Q: Find the equation of the normal line at 2 x = 0 to the curve, y + 0. x – 3 %3D -

A: Given: Equation of the curve…

Q: Find an equation of the normal line to the curve y = x1/2 that is parallel to the line 2x + y = 1.

A: To determine a normal to the curve which is parallel to the given line

Q: Find the equation of normal to the curve y = 2x – 4x² +x- 6 at point (2,–4)

A: Given y=2x3-4x2+x-6 and point is P(2,-4)We need to find the slope i.e. y'dydx=ddx(2x3-4x2+x-6)We…

Q: Find equations for the tangent line and the normal line to che graph x² + y? = 5, (2, 1) tangent…

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Q: Find the slope of the normal line y^2=1-x^2 at point (2,1)

A:

Q: Find an equation of the normal line to the curve y= sqrt(x) that is parallel to to the line 2x+y=1.

A: The equation of the curve is y=x and the equation of the line parallel to the normal line is 2x+y=1.…

Q: Find an equation of the normal line to the curve of y = x that is parallel to the line 6x + y = 1. y…

A: Draw the graph of the given curve and the given parallel line.

Q: Find the equations of the tangent and normal lines to the graph of  (x^2 + y^2)^3 = 8x^2y^2 at…

A:

Q: 2. What is the slope of the line tangent to the curve 8x³ - y² = 4 at the point (1,-2)? 3. What is…

A: In 2 we need to find the slope of the line tangent to the given curve at a point.  in 3 we need to…

Q: Find the equation of the tangent and normal line using the stipulated conditions   2.) x2 + 2y2 =…

A: The equation of tangent line is x2+2y2=9⇒x29+y292=1we have a=3 and b=92Since, we know that the…

Q: Find the equation of the line that is normal to the curve (y-x)2 = 2x + 4 at (6,2). %3D

A: Use equation of normal line

Q: 3. The normal line to the curve y = f (x) = 2x² at a point in the first quadrant passes through the…

A: Question is solved.

Q: (b) Find the equation of the normal to the curve 3x² +2y³ = 7xy at the point(2,1)

A: 3x2+2y3=7xy;(2,1)

Q: 8. Write the equation of the normal line to the curve In x+ ye =-e at (1,-1) in slope-intercept form…

A: Equation  of normal line y-y0= 1/(-dy/dx) (x-x0)

Q: Find the equation of the tangent line and the normal line of the curves at given point 1. x? + y? -…

A:

Q: Find the equation of the Normal Line to the curve y² = X at (4, 2)

A: Given that,Equation of the curve is y2=x We need to find the equation of the normal line to the…

Q: Find the equation of the normal line to the curve 2x/y - 3yvx + 5xy = 22 in the point (4, 1).

A: Given,         The curve is 2xy-3yx+5xy=22 in the point 4,1.