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Q1/ Determine the exit velocity of Air enters a diffuser at (80 kPa, 27°C) and (440 m/s) with a flow rate of (5 kg/s) and leaves the diffuser at (42°C). The exit cross section area of the diffuser is (800 cm2). T = 27°C = 300K T2 = 42°C = 315K = 300.19 kJ/kg - h - h2 = 315.27 kJ/kg

Q1/ Determine the exit velocity of Air enters a diffuser at (80 kPa, 27°C) and (440 m/s) with a flow rate of (5 kg/s) and leaves the diffuser at (42°C). The exit cross section area of the diffuser is (800 cm2). T = 27°C = 300K T2 = 42°C = 315K = 300.19 kJ/kg - h - h2 = 315.27 kJ/kg

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Q1/ Determine the exit velocity of Air enters a diffuser at (80 kPa, 27°C) and (440 m/s) with a flow rate of (5 kg/s) and leaves the diffuser at (42°C). The exit cross section area of the diffuser is (800 cm2). T = 27°C = 300K T, = 42°C = 315K = 300.19 kJ/kg - h2 = 315.27 kJ/kg %3D
Transcribed Image Text:Q1/ Determine the exit velocity of Air enters a diffuser at (80 kPa, 27°C) and (440 m/s) with a flow rate of (5 kg/s) and leaves the diffuser at (42°C). The exit cross section area of the diffuser is (800 cm2). T = 27°C = 300K T, = 42°C = 315K = 300.19 kJ/kg - h2 = 315.27 kJ/kg %3D
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