Q10) Based on this output, whichmedia issue might exist on the link?*Fast Ethernet0/1 is up, line protocol is upHardvare is AudFE, address is 0006.d7b2.clel (bia 0006. d7b2.clel)Internet address is 10.1.3.2/24MTU 1500 bytes, BW 100000 Kbit, DLY 100 usec,reliability 255/255, txload 1/255, rxload 1/255Encapsulation ARPA, loopback not setKeepalive set (10 sec)Half-duplex, 100Mb/s, 100BaseTX/FXARP type: ARPA, ARP Timeout 04:00:00Last input 00:00:00, output 00:00:00, output hang neverLast clearing of "shov interface" counters neverInput queue: 0/75/0/0 (size/aax/drops/flushes); Total output drops: 0Queueing strategy: fifoOutput queue: 0/40 (size/nax)5 ainute input rate 1000 bits/sec, 3 packets/sec5 ainute output rate 3000 bits/sec, 2 packets/sec980 packets input, 59426 bytesReceived 6 broadcasts, o runts, 0 giants, 0 throttlesO input errors,1589CRC,0 frame, 0 overrun, 0 ignoredO vatchdogO input packets vith dribble condition detected1868 packets output, 174674 bytes, 0 underrunsa) bandwidth on the interface ishigh.O b) faulty NIc.c) electrical interference and noiseon the link.d) the cable attaching the host toport Fa0/1 might be too long.e) the interface might be configuredas half-duplex.

Q10) Based on this output, which media issue might exist on the link? Fast Ethernet 0/1 is up, line protocol is up Har dvare is AadFE, address is 0006. 47b2.clel (bia 0006. d7b2.clel) Internet address is 10.1.3.2/24 MTU 1500 bytes, BV 100000 bit, DLY 100 usec, reliability 255/255, txload 1/255, rxload 1/255 Encapsulation ARPA, loopback not set

Q10) Based on this output, which media issue might exist on the link? Fast Ethernet 0/1 is up, line protocol is up Har dvare is AadFE, address is 0006. 47b2.clel (bia 0006. d7b2.clel) Internet address is 10.1.3.2/24 MTU 1500 bytes, BV 100000 bit, DLY 100 usec, reliability 255/255, txload 1/255, rxload 1/255 Encapsulation ARPA, loopback not set

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Answer the questions below about CSMA/CD protocol: i) Fill in the missing words in the gaps of the following text: “In CSMA/CD the ____________ (A) waits K ____________ (B) after a collision, where K is drawn ____________ (C). If you take the last three digits of your QMUL student ID as an example of value for K, the adapter would wait _________ (D) ____ __ (E) that corresponds to ___________ (F) miliseconds for a 5Mbps broadcast channel, ___________ (G) miliseconds for a 100Mbps broadcast channel, and ____________(H) miliseconds for a 1000 Mbps broadcast until returning to the step of sensing the channel.” Note: You are required to write down the gaps numbered A to H and show your calculations.
52- A network for a local office requires 4 LAN subnets as follows: · Subnet A - North Office with 31 hosts; · Subnet B - East Office with 15 hosts; and · Subnet C - South Office with 7 hosts. · Subnet D – West Office with 4 hosts. Given the IP Address 192.168.15.0 /24 and above described network requirements: 1. Design an optimal address scheme using Variable Length Subnet Mask (VLSM) method; What will be the subnet mask of Subnet A? Select one: A. 255.255.255.192 B. 255.255.128.255 C. 255.255.255.128 D. 255.255.192.192 E. 255.255.192.0
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b) Answer the questions below about wired LANs: i) Fill in the missing words in the gaps of the following text: “ In wired LANs, the de facto protocol used in the Data Link Layer is ____________ (A). In these LANs, two possible ____________ (B) structure standards can co-exist, they are the ____________ (C) standard and the _____________ (D) standard. The main difference between these two standards is a ____ __ (E) in the ___________ (F) of the MAC PDU that is also used to ___________ (G) the standards by its ____________(H).” Note: You are required to write down the gaps numbered A to H
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42. Though there are practical reasons why we don't complicate our lives this way in the real world, from a theoretical perspective we could borrow non-consecutive bits for subnetting. So, when borrowing the first host bit, the second host bit and the last two host bits (counting from the left of the host bit field) from 172.1.0.0 can you determine the following: a. subnet maskb. network address for 0th subnet, 1st subnet and 2nd subnet?c. total number of subnets and number of useable subnets?