Q10) Calculate the efficiency of water application if a watercourse of 0.085 m3/sec was supplied to a field for two hours, the averaged amount of runoff averaged 0.04 m3/sec for one hour, and depth of root zone depth is 1.5m. Assume there no evaporation losses has been occur. None of the above O 23.5 % 25 % 76.5 %
Q: The rainfall in four successive 12 hours period on a catchment are 40, 80, 90 and 30 mm. If the…
A: Given data : ϕIndex=5 mm/hourTime (t)=12 hour
Q: Exercise [21 For a given basin, the following are the infiltration capacity rates at various time…
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Q: For a given month a 100 acre lake has 10 cfs. of inflow , 8 cfs outflow total storage increase of 20…
A: write down the given dataInflow=10cfs=10 cubic feet/secoutflow=8 cfs=8 cubic feet/secfor…
Q: For a given basin, the following are the infiltration capacity rates at various time intervals after…
A: iv=5×160=0.0833v=5-3.9×160=0.01833Total rain = 2.2079Total excessive rain=1.35 cm
Q: a. Draw the hyetograph of this storm. b. Draw the standard infiltration curve (Using Horton's…
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Q: Calculate the runoff (cm) from a rainfall of 3 hours. The intensity of the rainfall is 2 cm/hr. The…
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Q: A soil has the effective moisture content is 0.35, its soll suction head is 9.0 cm, hydraulic…
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Q: An infiltration capacity curve prepared for a catchment indicated an initial infiltration capacity…
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Q: A 1000 acre reservior recieves 100 in of rain during a rainfall of 24 months. during this period,…
A: Given
Q: find the following : 1- Inflow discharge (cm/6-months) = ? 2- ΔS (cm/6-months)= ? 3-…
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Q: During a 6-hr. storm of uniform intensity of 1.5 cm/hr., the total runoff volume is 23.04*106 m³.…
A: Given data- 6-hour stormIntensity of storm I=1.5 cm/hr=1.5×10-2 m/hrTotal runoff volume R=23.04×106…
Q: A reservoir is in a region where the average annual precipitation is 3106 mm and normal annual US…
A: Solution Given data Pan Evaporation= 3456 mm Average area= 50 km2
Q: The moisture condition of a catchment soil previous a storm is known. Its infiltration capacity fp…
A: Given equation is as follows: fp=0.5+1.2e-0.5twhere,t is in hoursfp is in cm/hr
Q: A small public well is used to supply drinking water to a small residential community located in a…
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Q: average inflow of 6m^3/s from surface runoff. In the same period the outflow from the lake had an…
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Q: Q2 The average annual rainfall is 800 mm/yr in a catchment of 100 km2. In its original condition the…
A: Given: The catchment area is 100 km. The average annual rainfall is 800 mm/year. The average annual…
Q: A watershed 600 ha in area experienced a rainfall of uniform intensity 2.0 cm/h for duration of 8…
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Q: Knowing that the catchment area represented in the chart below is 20.3 km², calculate the volume of…
A: Area of the catchment = 20.3km2
Q: A catchment area of 120 sq km has three distinct zones, namely zone A with an area of 61 sq.km and…
A: Given data, Total area = 120 km² Zone A area = 61 km² & Runoff = 52 vm Zone B area = 39 km²…
Q: A catchment area 5000 km². In one day, the depth of precipitation is 55mm, Evapotranspiration is 0.8…
A: From given data: A=5000 km2=5×109 m2Vpresipitation=dpresipitation×A=0.055 m×5×109 m2=275×106…
Q: Clear lake has a surface area of 70.8ha. For a given month the lake has an inflow of 1.50m/s and an…
A: Evaporate occurs when the water changes from a liquid to a gas or vapor. The cool-down working…
Q: A watershed 600 ha in area experienced a rainfall of uniform intensity 2.0 cm/h for duration of 8…
A: Given data Area of watershed (A) =600 ha = 600*104 m2 Uniform intensity of rainfall (i) = 2.0 cm/h…
Q: Exercise [2] For a given basin, the following are the infiltration capacity rates at various time…
A: From the above data, The F-time curve:
Q: A catchment area 5000 km2. In one day, the depth of precipitation is 55mm, Evapotranspiration is 0.8…
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Q: Q-3: Determine the discharge of a distributary at the tail end from the following data: Gross…
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Q: О. No. 03; A stream of 135 L/s was diverted from a canal and 100 L/s were delivered to the field. An…
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Q: If the mean annual runoff of a drainage basin of 10,000 km2 is 140 m2/s , and the average annual…
A: Area = 10000km2Discharge = 140m2sAnnual runoff = 140m3s Change in storage, groundwater flow, and…
Q: A small catchment area 300 km2 received a rainfall of 15cm in 1 hour, due to a storm draining the…
A: Given: Catchment area = 300 km2Rainfall = 15 cmRainfall duration = 1 hrRunoff duration = 5…
Q: Assuming the parameters for Philip’s equation are sorptivity, S = 6 cm/hr and K = 0.3 cm/h.…
A: Given :- Sorpitivity, S = 6 cm/hr The hydraulic conductivity (K) = 0.3 cm/h To determine :- The…
Q: Q2: A small catchment of area 90 ha received a rainfall of 75 mm in 60 minutes due to a storm. At…
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Q: The Horton's infiltration equation for a basin is given by f= 6 + 15 e 2t where fis in mm/hr and t…
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Q: A watershed 600 ha in area experienced a rainfall of uniform intensity 2.0 cm/h for duration of 8…
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Q: 2. A 15mm rainfall is recorded over a small catchment according to the table below. Infiltration…
A: Infiltration capacity: Water on the earth's surface penetrates the soil through this procedure. It…
Q: Q2: During a three-hour storm, the rainfall over a 100 ha area is 4 cm. There is a constant…
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Q: 1. The initial infiltration capacity f0 of a watershed is estimated as 1.5 in./hr, and the time…
A: Thank you for the question. As per honour code we will answer the first question since exact one was…
Q: For a small drainage area, the infiltration rate at the start of rainfall storm was record to be 90…
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Q: Exercise [1] For a small drainage area, the infiltration rate at the start of rainfall storm was…
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Q: Q2- A cumulative runoff depth 33mm , determine Ø - index and estimate volume of infiltration in…
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Q: 7. The initial infiltration capacity fo of a watershed is estimated as 4 cm/h and the time constant…
A: A.) We have f0=4 cm/hr fc = 0.5 cm/hr…
Q: A catchment has four sub-areas. The annual precipitation and evaporation from each of the sub-areas…
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Q: A community receives 0.50 m³/s of flow into its wastewater treatment plant. The total surface area…
A: Given data, Flow rate Q = 0.5 m^3/s Surface area of primary clarifiers A = 2700 m^2 Retention time t…
Q: A lake with a surface area of 3,250 acres was monitored over a period. During a three-month period,…
A: Surface area of lake, A =3250 acres.During a 3 month period, Inflow =52 ft3sOutflow =41 ft3sSeepage…
Q: The uniform precipitation over a catchment area covering 80 km2 received a total precipitation of 80…
A: From the conservation of mass, Total inflow per unit time=Total outflow per unit time+∆s
Q: A catchment area of 140 km2 received 120 cm of rainfall in a year. At the outlet of the catchment…
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Q: The 4 hourly rainfall data are given below. fo the initial value of the infiltration capacity is 6…
A: Given data Intial infiltration (fo) = 6mm/ hr Steady or limiting infiltration capacity (f0) = 2mm/hr…
Q: An infiltration capacity curve prepared for a catchment indicated an initial infiltration capacity…
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Q: A discharge of 0.15 cumecs is supplied into a canal at the head and 0.1 cumecs is delivered to field…
A: Note - : Since we only answer up to 3 sub-parts, we’ll answer the first 3. Please resubmit the…
Q: A lake with a surface area of 750 acres was monitored over a period of time. During a one-month…
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Q: For a small drainage area, the infiltration rate at the start of rainfall storm was record to be 90…
A: Develop the Horton equation for infiltration rate at t<2.5 hr
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- Determine the water-application efficiency, the water-storage efficiency, and the water-distribution efficiency for the following conditions: stream of 80 lps delivered to the field for 5-hours, runoff averaged 40 lps for 2.5 hr, depth of root zone was 1.8 m, depth of penetration varied linearly from 1.8 m at one end to 0.6 m at the other end of the field. Ans. 76.5%, 66.7%, 90.6%A catchment area of 150km 2 received a 150 cm of rainfall in a year. At theoutlet of the catchment the flow in the stream draining the catchment wasfound to have an average rate of 2.0m 3 /s for 3 months, 3.02.0m 3 /s for 6months and 5.02.0m 3 /s for 3 months. (a) what is the runoff coefficient of thecatchment? (b) If the afforestation of the catchment reduces the runoffcoefficient to 0.50, what is the increase in the abstraction from precipitationdue to infiltration, evaporation and transpiration, for the same annual rainfallof 150 cm.Answer these both questions a. The total observed runoff volume during a 4 hr storm with uniform intensity of 2.8cm/hr is 25.2 x106 m3 from basin of 280km2 area. What is the average infiltration rate for the area. b. A volume of 3x106 m3 of groundwater was pumped out from unconfined aquifer uniformly over an area of 5 km2. The pumping lowered the water table from 102 to 99m. The specific yield of the aquifer is?
- A discharge of 0.15 cumecs is supplied into a canal at the head and 0.1 cumecs is delivered to field having an area of 1.5 hac. The Irrigation is started at a moisture extraction level of 60% of the available moisture and then extends for 10 hours. Determine the following efficiencies: water conveyance, water application, water storage, and water distribution. The following information are known: effective depth of r.z. = 1.7 m, runoff loss in the field = 425 m3 , water penetration depth varies linearly from 1.7 m at the head end of the field to 1.1 m at the tail end, W.H.C. = 25cm/m depth of soil.A lake with a surface area of 3,250 acres was monitored over a period. During a three-monthperiod, the inflow was 52 cfs, the outflow was 41 cfs, and 5.25 in. of seepage loss was measured.During this same time period, the total precipitation recorded was 7.25 in. and evaporation losswas estimated to be 4.5 in. Estimate the change in storage for this lake during the time period,in inchesSubject: Hydrology Give me right solution Determine the 10-year period peak runoff for 80 hectare watershed having a runoff coefficient of 0.4. The maximum length of flow of water is 610 meters and the fall along this path is 6.0 meters. The rainfall intensity for that return period is 101.25 mm/hr having duration equal to the time of concentration.
- Estimate ∅-index for a watershed having an area 5 acres. The runoff volume caused by the rainfall is 56000 ft^3. Round off your answer to the nearest whole number. Indicate the unit. Plot the hyetograph and superimpose the final ∅-index. (1 acre = 43560 ft^2) * Using the rounded-off ∅-index, estimate the volume of infiltration losses in cubic feet. *A catchment has 4 sub areas (see table below). The annual precipitation andevaporation from each of the sub areas are given below. Assume that there is no change inthe groundwater storage on annual basis and calculate for the whole catchment the valuesof annual averageA. Precipitation (Ans. P ave = 1105.167 mm)B. Evaporation (Ans. E ave = 532.416 mm)C. What are the annual run-off coefficients for the subareas and for the totalcatchment area as a whole? (Ans.ratio = 0.508)Compare/contrast the following quantities from each other:rainfall rate and infiltration capacityrainfall rate and infiltration rateinfiltration capacity and infiltration rate
- 4.If the mean annual runoff of a drainage basin of 15,000 km2 is 165 m3/s, and the average annual precipitation is 135 cm. Estimate the ET losses for the area in 1 year. 5. A lake with a surface area of 3,250 acres was monitored over a period. During a three-month period, the inflow was 52 cfs, the outflow was 41 cfs, and 5.25 in. of seepage loss was measured. During this same time period, the total precipitation recorded was 7.25 in. and evaporation loss was estimated to be 4.5 in. Estimate the change in storage for this lake during the time period, in inchesCalculate the runoff from a watershed of (0.01 x 4737) ha. The following data are available: Depth of rainfall is 100 mm. Antecedent rainfall condition, AMC 1: Row crop, good condition in 40 ha (Soil group C) Woodland, good condition in 20 ha (Soil group B) The day after the rainfall of 100 mm, another rainfall of 50 mm occurred. Solve for the surface runoff from the watershed. [ NOTE: Where R is the last four digits of your Registration Number. R = 4737 ]Determine the required area (in ft ) of a bioretention basin to service runoff from a shopping complex with 4 .2 acres of paved parking, 1.1 acre of sidewalks, 0.5 acre of landscaping. The 24-hr design storm is 1 inch. Use the empirical coefficients in Small Storm Hydrology method. There is no underdrain pipe for the bioretention basin. Use the following guidelines for the design: Ponding depth = 12 inch Media bed: 36 inches deep, porosity = 0.30 Gravel bed: 24 inches deep, porosity = 0.36