Q2: A DC circuit comprises three closed loops. Applying Kirchhoff's laws to the closed loops gives the following equations for current flow in milliamps: 3 I1 + 412 + I3 -10 =0 2 I1 -312 +5 I3= 0 I + 212 - I3 -6 =0 1. Use the determinants to solve for I, I2, and I3. 2. Repeat solution using cramer's rule?

Q2: A DC circuit comprises three closed loops. Applying Kirchhoff's laws to the closed loops gives the following equations for current flow in milliamps: 3 I1 + 412 + I3 -10 =0 2 I1 -312 +5 I3= 0 I + 212 - I3 -6 =0 1. Use the determinants to solve for I, I2, and I3. 2. Repeat solution using cramer's rule?

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter9: Systems Of Equations And Inequalities

Section9.9: Properties Of Determinants

Problem 36E

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