Q#2 (a) The relation for total energy (E) and momentum (p) for a relativistic particle is E = c²p² + m²c*, where m is the rest mass and c is the velocity of light. Using the relativistic relations E= ho and p= ħk, where o is the angular frequency and k is the wave number, show that the product of group velocity and the phase velocity is equal to c?.
Q#2 (a) The relation for total energy (E) and momentum (p) for a relativistic particle is E = c²p² + m²c*, where m is the rest mass and c is the velocity of light. Using the relativistic relations E= ho and p= ħk, where o is the angular frequency and k is the wave number, show that the product of group velocity and the phase velocity is equal to c?.
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![Q#2 (a) The relation for total energy (E) and momentum (p) for a relativistic particle is E = c² p² + m²c*, where
m is the rest mass and c is the velocity of light. Using the relativistic relations E = h w and p = hk, where w is
the angular frequency and k is the wave number, show that the product of group velocity and the phase velocity
is equal to c2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc5f8e218-6491-4722-a470-335e3cb74611%2F182e1436-6112-4a9d-8d8d-5ee82b7ebcf9%2F5m6osg4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Q#2 (a) The relation for total energy (E) and momentum (p) for a relativistic particle is E = c² p² + m²c*, where
m is the rest mass and c is the velocity of light. Using the relativistic relations E = h w and p = hk, where w is
the angular frequency and k is the wave number, show that the product of group velocity and the phase velocity
is equal to c2.
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