Q3) Compute the weakest precondition for the following selection construct and its post-condition if (x < y) y = 2 * x - 4; else y = 2 *x + 4; {Q: y < 10}
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- Compute the weakest precondition for each of the following assignment statements and postconditions. x = 2 * y -5; y = x + 2; {y < 2}Write assignment statements for the following: Assign a value of 1 to between if n is in the range -k through +k, inclusive; otherwise assign a value of 0 Assign a value of 1 to uppercase if ch is an uppercase letter; otherwise, assign a value of 0. Assign a value of 1 to divisor if m is a divisor of n; otherwise, assign a value of 0.a- Rewrite the following code segment using a multiple selection statement in thefollowing languages C, C++, or Java (Assume all variables are integer type):if (k = 1) or (k = 2) then j := 2 * k -1if (k = 3) or (k = 5) then j := 3 * k + 1if (k = 4) then j := 4 * k - 1if (k = 6) or (k = 7) or (k = 8) then j := k – 2 b- Consider the following case statement. Rewrite it using only two-way selection.case index - 1 of:2, 4: even := even + 1;1, 3: odd := odd + 1;0: zero := zero + 1;else error := trueend case
- 1. Give the unifyiing substitition for (x,y,z are variables): f(a) f(b) 2. Give the unifyiing substitition for (x,y,z are variables): g(x,x) g(f(a),f(y)) 3. Give the unifyiing substitition for (x,y,z are variables): g(x,x) g(f(a0,f(b))- Pure Javascript in console- Use camelCase- use functions to call each case- all cases must be user inputWrite a C++ function weird_sum that takes two integer parameters, n1 and n2. The function returns the sum of n1 and n2, as long as their sum is not a multiple of 13. If their sum is a multiple of 13, the function returns 3 less than the sum of n1 and n2.
- explain friend functions.Write a function median : int * int * int -> int that returns the median value of the input. You may assume that no 2 numbers are equal. For example median (1,3,2) returns 2 IN SML ONLY and use pattern matching pleaseCompute the weakest precondition for each of the following assignment statements and selection constructs. Detailed steps are needed. a = 2 * (b - 1) - 1 {a > 0} a = 2 * b + 1 b = a - 3 {b < 0} if (a == b) b = 2 * a + 1 else b = 2 * a {b > 1}