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- Q: A bit stream 1011000 is transmitted using the standard CRC method. The divisor is 1011. What is the actual bit string transmitted? Also find out whether, there is an error or not?Which of the following encoding methods does not provide for synchronization? a. NRZ-L b. RZ c. NRZ-I d. ManchesterQuestion 5 You are given a cover image with the following nine bytes of data. Hide the payload 110101000 in the cover image. How many bits did you have to change? 11010011 00001111 00110011 10101010 00110010 01010101 10010010 00010001 10010011 Full explain this question and text typing work only thanks
- A bit string contains 1's and 0's. How many different bit strings can be constructed given the restriction(s)? Length is 20. Has exactly six 1's in the first half. Has exactly three 1's in the second half.How many bit strings of length 10 contain a) exactly four 1s? b) at most four 1s? c) at least four 1s?Four computers are sending the digital data over a multiplexed line as shown in the Figure below. A). Show how the messages are multiplexed into frames using synchronous TDM and Asynchronous TDM. B). How many frames are generated if you are using Synchronous TDM? C.) How many frames are generated if you are using asynchronous TDM with frame size 3?
- Dear Writer this is my calculation solution.could you please double check it and let me know it if it soccrect or should i proceed with your solution: Please provide justification if correction is need and correct answer.Thank you in advance. a) The transmission time of a frame can be calculated as follows: Propagation delay (Tp) = distance/speed = 5km / 200000 km/s = 0.0025ms Transmission time (Tt) = frame size/bandwidth = 10000 * 8bits / (1Mbps * 10 ^ 6) = 0.008sec = 8ms Total time for transmission = 2 * Tp + Tt(since the frame has to travel from A to D and then D to A) = 2 * 0.0025ms + 8ms = 0.005ms + 8ms = 8.005ms The transmission time of the frame from A to D is 8.005 ms. b) The efficiency of the CSMA/CD protocol is given by the formula: Tt is the transmission time of a frame C is the number of collisions, Tp is the propagation time of a signal from one end of the segment to the other. Efficiency = Tt / (C * 2 * Tp + Tt + Tp) Assuming that there are no other…For the bit stream 01001110, sketch the waveforms for each of the codes. Assume that the signal level for the preceding bit for NRZI was high; the most recent preceding 1 bit (AMI) has a negative voltage; and the most recent preceding 0 bit (pseudo temary) has a negative voltage.A bit stream 10011101 is transmitted using CRC method. The generator polynomial is x^3 + 1. Show the actual bit string transmitted. Suppose the third bit from the left is inverted during transmission. Show that this error is detected at the receivers end.
- What is the probability that a bit string of length 8 has exactly five 1’s?Please step by step calculations! Using the insertion principle of Flags and the transparency bits, encode this frame from right to left The result frame should be ready for transmission . 011111010101111110101011111111101110111111Encode the following bit stream, 01001101 with the following encoding schemes: a) NRZ-L b) NRZ-I c) AMI d) Manchester e) Differential Manchester f) Bipolar g) NRZ