Q3 In a company, there are several branches. Let us consider a branch of that company having N employees, if the manager is allotted to that branch(s) then he is known to everyone else in that branch. Note that the property of "known to everyone" is unique to a manager. Your task is to find the manager in that branch. Input from the user in main (), the square matrix M where if an element of row i and column j is set to 1 it means that ith person knows jth person. You need to write a function managerId () which returns the id of the manager if present or else returns -1. The function managerId () takes two arguments - the square matrix of N *N and its size N. Call managerId () from the main () output the information about the manager. Assume all diagonal elements to be 1 (as everyone knows him/herself) and there is at most one manager in the company. Example: No of persons N = 3

Computer Networking: A Top-Down Approach (7th Edition)
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Author:James Kurose, Keith Ross
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Q3 In a company, there are several branches. Let us consider a branch of that company having N
employees, if the manager is allotted to that branch(s) then he is known to everyone else in that
branch. Note that the property of "known to everyone" is unique to a manager. Your task is to find
the manager in that branch. Input from the user in main (), the square matrix M where if an element
of row i and column j is set to 1 it means that ith person knows jth person. You need to write a
function managerId () which returns the id of the manager if present or else returns -1. The function
managerId () takes two arguments - the square matrix of N *N and its size N. Call managerId ()
from the main () output the information about the manager. Assume all diagonal elements to be 1
(as everyone knows him/herself) and there is at most one manager in the company.
Example:
No of persons N = 3
Input matrix:
0 1
1 1
0 1
Output: manager is person 3
1
0
1
Transcribed Image Text:Q3 In a company, there are several branches. Let us consider a branch of that company having N employees, if the manager is allotted to that branch(s) then he is known to everyone else in that branch. Note that the property of "known to everyone" is unique to a manager. Your task is to find the manager in that branch. Input from the user in main (), the square matrix M where if an element of row i and column j is set to 1 it means that ith person knows jth person. You need to write a function managerId () which returns the id of the manager if present or else returns -1. The function managerId () takes two arguments - the square matrix of N *N and its size N. Call managerId () from the main () output the information about the manager. Assume all diagonal elements to be 1 (as everyone knows him/herself) and there is at most one manager in the company. Example: No of persons N = 3 Input matrix: 0 1 1 1 0 1 Output: manager is person 3 1 0 1
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