Q3 Let U = {5, 6 }, write an equivalent to the following assertions: 3x P ( x ) v - Vx Q ( x )
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A: Answer : True
Q: 04 what is the result of following if: a=3, b=3? i- ab iv- a>=b V- a==b vi- a!=b
A: Implementing the above statements through C++ langauge. #include <iostream>using namespace…
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A: The output of the given c++ program is discussed below.
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A: 6/3+7/2 It will solve according to operator precedence 6/3=2 7/2=3.5 6/3+7/2=5.5
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A:
Q: What are the values of a, b, c, d, and e after the following statements? int a = -2, b = 5, c = 1,…
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Q: Part A part B What is the value of X after solving the following equation? X = ((5^2/5) ^2 +5)- 10…
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A: Here, we are going to find out cardinality of set A and also find out the subsets of given set A.
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A: Here first we can do (A^B) which is A AND B And then OR the result with C.
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Q: Q3\A) Evaluate the following expressions with explanation for each one: : int x= 10, y=8, z; 4-…
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Q: Q3\A) Evaluate the following expressions with explanation for each one: int x= 10, y=8, z; 1- z=…
A: As per answering guidelines solving the first question completely. x=10, y=8 1) z=++x - y-- z=…
Q: int active(Int x) If (x < 1) return 10; else return active(x- 2)+x3;
A: I have given an answer in step 2.
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Q: G(end/3)=, 6- If G=[20, 9, 15, 10, 0, 8, 5], then G(1:3:end)= 7- If H=[6, 2, 8; 5, 3, 0; 11, 4, 1],…
A: AS per our policy we can only solve one question if the quesitons are not related and 3 questions if…
Q: Q3\A) Evaluate the following expressions with explanation for each one: ( int x= 10, y=8, z; 1- z=…
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Q: Implement the below application which identifies and displays the first na First Name
A: code is below:
Q: Suppose that Q(x) is "x+1 = 2x", where x is a real number. How many of the following statements are…
A: The solution to the given question is:
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A: The problem is based on the basics of discrete mathematics and boolean algebra.
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Q: 2. Show that following statements are correct: i. 4n+100-0(n) iii. n' + O(n?) v. n! = 0(n") vii. 3n…
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Q: What is the result after execution of the following code: int i 1, x 4: while (++i <= 10) { x++:…
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Q: Q3\A) Evaluate the following expressions with explanation for each one: (5 only) int x= 10, y=8, z;…
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Q: int y = !(12 x) ? 7 : 9 Based on the code above, what is the value of y if x = 1?
A: This question comes from Programming Language which is a paper of computer science. Let's discuss it…
Q: 5. Implement fl(x2, x₁) = Σ 0,3, and £2(x2, x₁) = 0,1,2, using a 4×2ROM? ✓ CI Familia v
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Q: Given: int d=2, e=4; bool f = 0; %3D f = (e%d==0); What is the final value of f?
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Q: int = (0,0,1); for (int i=0;i0) D[i][j] = i*j; else D[i][j] = i + j; c[i]+= D[i][j]; }
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Q: real :: 5.0, is a valid declaring of x = 5? *
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Q: Show that the following statement is true: n?ε Ω(nlog n)
A:
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- Complete the assignment. Compute allWrite a method that displays an n-by-n matrix usingthe following header:public static void printMatrix(int n)Each element is 0 or 1, which is generated randomly. Write a test programthat prompts the user to enter n and displays an n-by-n matrix. Here is asample run: Enter n: 3 ↵Enter0 1 00 0 01 1 1Q5. Write a program that reads from the user an integer matrix with 10x10, and then rotate that matrix 180° (UPSIDE DOWN) after that, calculate the sum and the average of the main diagonal. Print the matrix after the rotation and the values of the sum and the average of the main diagonal.
- briefly comment the code#include <stdio.h>#include <stdlib.h>/* ADJACENCY MATRIX int source,V,E,time,visited[20],G[20][20];void DFS(int i){int j;visited[i]=1;printf(" %d->",i+1);for(j=0;j<V;j++){if(G[i][j]==1&&visited[j]==0)DFS(j);}}int main(){int i,j,v1,v2;printf("\t\t\tGraphs\n");printf("Enter the no of edges:");scanf("%d",&E);printf("Enter the no of vertices:");scanf("%d",&V);for(i=0;i<V;i++){for(j=0;j<V;j++)G[i][j]=0;}/* creating edges :P */for(i=0;i<E;i++){printf("Enter the edges (format: V1 V2) : ");scanf("%d%d",&v1,&v2);G[v1-1][v2-1]=1; } for(i=0;i<V;i++){for(j=0;j<V;j++)printf(" %d ",G[i][j]);printf("\n");}printf("Enter the source: ");scanf("%d",&source);DFS(source-1);return 0;}Debug the following program and answer the following questions. #include <stdio.h> typedef struct node { int value; struct node *next; } node; int ll_has_cycle(node *first) { node * head = first; while (head->next) { head = head->next; if (head == first) return 1; } return 0; } void test_ll_has_cycle(void) { int i,j; node nodes[5]; for(i=0; i < sizeof(nodes)/sizeof(node); i++) { nodes[i].next = NULL; nodes[i].value = i; } nodes[0].next = &nodes[1]; nodes[1].next = &nodes[2]; nodes[2].next = &nodes[1]; printf("Checking first list for cycles. There should be a cycle, ll_has_cycle says it has %s cycle\n", ll_has_cycle(&nodes[1])?"a":"no"); printf("Checking length-zero list for cycles. There should be none, ll_has_cycle says it has %s cycle\n",…int a[10] = {0,1,2,3,4,5,6,7,8,9};int *m = &a[0];int *p = &a[5];int *q = &a[1]; p = (int) m + (int) p - (int) q; what is the value of of *p
- Can you answer it based on the code below: #include #define MAX_EMP 5 struct Employee { int id; int age; float salary; }; int count = 0; struct Employee emp[MAX_EMP]; void display() { printf("\n---=== EMPLOYEE DATA ===---\n"); printf("EMP ID\tEMP AGE\tEMP SALARY\n"); printf("======\t=======\t==========\n"); for(int i = 0; i < count; i++) { printf("%d\t%d\t%.2f\n", emp[i].id, emp[i].age, emp[i].salary); } } void add() { if(count == MAX_EMP) { printf("\nERROR!!! Maximum Number of Employees Reached\n"); return; } printf("\nAdding Employee ===============\n"); printf("Enter Employee ID: "); scanf("%d", &emp[count].id); printf("Enter Employee Age: "); scanf("%d", &emp[count].age); printf("Enter Employee Salary: "); scanf("%f", &emp[count].salary); count++; } void update() { int id, found = 0; float newSalary; printf("\nUpdate Employee Salary…INT_MIN = -32767 def cut_rod(price): """ Returns the best obtainable price for a rod of length n and price[] as prices of different pieces """ n = len(price) val = [0]*(n+1) # Build the table val[] in bottom up manner and return # the last entry from the table for i in range(1, n+1): max_val = INT_MIN for j in range(i): max_val = max(max_val, price[j] + val[i-j-1]) val[i] = max_val return val[n] # Driver program to test above functionsarr = [1, 5, 8, 9, 10, 17, 17, 20].Language: C Pascal’s triangle is a triangular array, useful for calculating the binomial coefficients, n k , that are used in expanding binomials raised to powers, combinatorics and probability theory. 0 0 1 0 1 1 2 0 2 1 2 2 3 0 3 1 3 2 3 3 4 0 4 1 4 2 4 3 4 4 Evaluating the values of the binomial coefficients, you get the following pattern, 1 1 1 1 2 1 1 3 3 1 1 4 6 4 1 The number of the entries in each row is increased by one, as we move down. Each number in the triangle, is constructed by adding the number above it and to the left, with the number above it and to the right. The blank entries as treated as 0. Using the recursion, implement the function that computes the Pascal’s triangle. Pr
- I'm C# implement a method that squares passing variables and returns their sum based on the Sum of Squares algorithm below (image attached).equality (5)/(9)x+(0)/(2)>=(5)/(2)x+(1)/(6). Enter your answer using intDevelop the program so that the user will be able to dynamically enter any amount of numbers. Afterwards, identify which of these elements are of perfect squares. Then display the identified perfect squares together and their sum