Q3:calculate the head water at entrance of box culvert (2x2 m & 30 M length) shown in Fig.2 for discharge (Q=6m'/sec) Use the following data: -head loss coefficient at entrance ( Ke-0.5 )& for down stream (Kd-1) -Manning's coefficient n=0.013.

Q3:calculate the head water at entrance of box culvert (2x2 m & 30 M length) shown in Fig.2 for discharge (Q=6m'/sec) Use the following data: -head loss coefficient at entrance ( Ke-0.5 )& for down stream (Kd-1) -Manning's coefficient n=0.013.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: A culvert is going to be designed at the cross-location between a river and a railway. Flood…

A: Discharge formula : Q =A*(R23*S12n) Q : discharge or flow rate A : area A=πDL L : length R :…

Q: Q1: A box culvert of (3×3)ft designed to accommodate 135 ft³/sec. the culvert length and slope are…

A: Given, Q = 135 cfs L = 100 ft S = 2.5% TW = 5 ft

Q: Water with density of 1000 kg/m and viscosity of 0.001 Pas is to flow from reservoir A to reservoir…

Q: Two horizontal pipes in series , each 1000 ft long and discahrges water at the rate of 4.75 ft^3/s,…

Q: Compute the velocity of the flow for a very smooth pipe if the hydraulic radius is 10ft, and slope…

A: we have hazen williams equation:V=1.318CR0.63S0.54so,C=coefficient ; for smooth pipe…

Q: The ratio between the discharge and top width of a best hydraulic rectangular channel is (91/50) ,…

A: Given,The ratio between the discharge and the top width, QT = 9150Bed slope, S = 13000 and C = 50For…

Q: D = 5.50 ft y = 0.8250 ft A circular culvert with diameter D = 5.50 ft and roughness coefficient n =…

Q: 1 20 Find the dimensions and the number of vents for the road crossing structure (Box Culvert) from…

A: Road culverts are provided to outflow of water from one place to another without disturbing the…

Q: In a circular channel 2.5meters in diameter, flowing below half full, the water surface width is…

Q: AR²/351/2 Derive Manning's equation for turbulent and uniform flow: Q = where Q is " n in m³/s; A,…

Q: EXAMPLE 1: Determine the normal discharge for the channel shown in Fig 2.7a. The water surface in…

A: Discharge is the volumetric flow rate of water that is transported through a given cross-sectional…

Q: a total discharge (4.5 cumecs), if the length of each one is 20 m at slope 1/ K1=0.5, K2= 1, n=…

A: Discharge on each culvert is Q=4.52=2.25m3sv=QAR=AP=π4D2πD=D4

Q: Hydraulics-Q.46.Find the depth, specific energy and slope for critical flow condition for given…

A: Given data Discharge Width To find Depth Specific energy Slope Assuming mannings roughness…

Q: 2. Water flows from left to the right reservoir at a rate of 16 ft3/s (cfs). The head loss can be…

A: Given Data: Flowrate (Q) = 16 ft3/s L1 = 200 ft L2 = 300 ft D1 = 1.128 ft D2 = 1.596 ft A1 = 1 ft2…

Q: 1. Design a pipe culvert using the following data. culvert. Discharge in the stream: 4 m/s Road top…

Q: Determine the maximum flow through a 1.65m diameter concrete culvert which is laid on a slope of…

A: D=1.65m d=0.938D n=0.012 S=0.0055

Q: Determine the probable discharge in a concrete culvert, 1.25 m diameter and under a head of 1.7 m if…

A: Given: The diameter is 1.25 m. The head is 1.7 m. The length is 13 m. The value of C is 0.74.

Q: Two reservoirs are connected by a pipeline consisting of pipe 1, pipe 2, pipe 3

Q: Q3: A box culvert (1mx1m) with Headwater, H=1.15 and built on steep slope equal to 0.008. Identify…

A: n = 0.013 Ke= 0.5 So= 0.008 TW = 0.45 HW = 1.15

Q: A trapezoidal weir having side slopes of 4:5 (Horizontal to Vertical) and 1:1 (Horizontal to…

A: Slopes- 4:5 (Horizontal to Vertical) 1:1 (Horizontal to Vertical) Discharge- Q = 2 m3 Head on the…

Q: A box culvert, as shown in the figure, was designed to carry a discharge (Q m'is) from a square…

Q: In culverts design under outlet control, if the desired Manning coefficient is 0.02. The corrected…

A: 1- If the desired manning's coefficient is 0.02 the culvert length can increase or decrease…

Q: A rectangular channel 3.6m x 1.8m deep discharge 6.8 cu.m per sec. If the same consideration have…

Q: Determine the culvert size (i.e. diameter, D) required for the following design conditions: culvert…

Q: The siphon in Figure 4 is a pipe of diameter D= 0.4 m with roughness ɛ = 0.4 mm. – Calculate the…

A: step 1-

Q: A concrete pipe culvert 3 ft in diameter and 10 m long has a difference in water level at the outlet…

Q: Example 3.3. A single looped network as shown in Fig. 3.10 has to be analyzed by the Hardy Cross…

A: Step 1

Q: A hydraulic jump occurs in a trapezoidal channel with side slope of 1V:2H and base width of 3.8m if…

A: Given Data: The slope of the channel is 1V: 2H. The base width of the trapezoidal channel is b = 3.8…

Q: P2: For a given dam in the following figure, (a) Draw the flow net by using Nr= 3 and Na=6.5. (b)…

A: The small squares near dam bottoms have a high rate and quantity of water flow. Flow lines are made…

Q: A contracted rectangular weir 10.0 ft long discharges water under a head of 147/16 in. Compute the…

A: Solution: Given: Length of weir(L)=10ft Head (H)=147/16=9.18in=0.765ft By the Francis correction…

Q: H.W.: A concrete pipe culvert is to be constructed under road to carry a maximum discharge 9 m2/sec.…

A: The given data is: Discharge, Q=9m3/s Length of the pipe, L=10 m Slope, s=1/100

Q: Q3/ determine the discharge in the compound open channel shown in figure assume a bed slope (O.001)…

A: Bed slope (s) = 0.001 Mannings coefficient (n) = 0.03 Area of channel (A) = ( 5 x 0.5 ) + ( 0.2 x…

Q: #Q 3.5.3 A Flow net is plotted for a homogeneous earthern dam of 30.0 m height with a free board of…

A: Given data,

Q: A test measurement of flow over a standard weir 300 mm high in a flume 0.609 m wide at a head of…

A: Flow over weir = 300mm = 0.3m Width = 0.609m Head = 0.158m Total Volume (V) = 26.68 m3 Time (t) =…

Q: Two horizontal pipes in series , each 1000 ft long and discahrges water at the rate of 4.75 ft^3/s,…

Q: EXAMPLE 1: Determine the normal discharge for the channel shown in Fig 2.7a. The water surface in…

A: Flow in most channels is turbulent, and laminar flow in open channels is very rare. Laminar…

Q: A trapezoidal channel of 2.0m bed width and 3:2 side slope carries a discharge of 10m3/sec with a…

A: Given Data: The bed width of the channel is b=2 m. The side slope of the channel is 3:2. The depth…

Q: A trapezoidal channel carries 1.2 m/s of flow on a longitudinal slope of 0.003. If channel surface…

A: trapezoidal channel carries 1.2 m3/sec of flow on longitudinal slope 0.003 . chezy formula Q=…

Q: Q1: Design a pipe aqueduct on branch rectangular channel with the following information: Flow rate…

A: The flow of fluid includes movement of an unbalanced fluid. As long as unequalled forces are in…

Q: Hydraulics-Q.46.Find the depth, specific energy and slope for critical flow condition for given…

A: Applying standard results for rectangular channel

Q: 4) Two box culverts each is 0.61 m by 0.61 m and has n = 0.013, Kẹ = 0.05, Cd = 0.85, L = 30 m, So =…

A: Given: n=0.013Ke=0.05Cd=0.85L=30mSO=0.7%HW=1.5mTW=O.84m Area of Culvert=0.61×0.61…

Q: Find the flowrate (in cubicmeter/ second). 11 = 1.6 m Discharge P = 1 m W Broad-crested weir

A: given- Length of the weir B= 1 mHead over weir H=1.6 m

Q: 4. Determine the flow over a suppressed weir 3 m long and 1.2 m high under a head of 900 mm. The…

A: Q= 5.143 m3/sec

Q: Determine whether a 1.5 m × 1.5 m reinforced concrete box culvert with 45° flared wing- walls and…

A: Procedure: first, calculate the flow rate per width Then calculate the required headwater and…

Q: H.W.: A concrete pipe culvert is to be constructed under road to carry a maximum discharge 9 m3/sec.…

A: Given - Discharge = Q = 9m3secLength of pipe = L = 10mSlope = S = 1100 Formula used - By…

Q: Two reservoirs are connected by a pipeline consisting of pipe 1, pipe 2, pipe 3 connected in series…

A: Given, L1 = 170 m L2 = 300 m L3 = 210 m

Q: Find the length of the crest using integration.

Q: Two reservoirs are connected by a pipeline consisting of pipe 1, pipe 2, pipe 3 connected in series…

Q: The maximum flow rate can be conveyed by a pipe with a diameter of 400 mm and an absolute roughness…

A: Given data- Diameter of pipe(D) = 400mm = 0.4 m Roughness (n) = 0.5 Hydraulic slope (S) = 0.0025…

Concept explainers

Sediment transport

Sediment transport or Soil transport is the movement of solid particles, usually due to the combination of gravitational forces acting on the sediment, and the movement of the liquid at which the sediment enters. Soil erosion occurs in natural systems where the particles are sandstones (sand, rocks), mud, or clay; the liquid is air, water, or ice; and the gravitational force that works to move particles to the landing surface. Sediment transportation or soil migration due to the movement of liquids occurs in rivers, lakes, lakes, oceans, and other bodies of water as a result of currents and waves. Transportation is also caused by glaciers as they flow, and to places on earth under the influence of wind. Soil erosion due to gravity alone is possible in most sloping areas, including hills, scarves, cliffs, and the continental shelf — the continental boundary of the slope.

Question

100%

Q3:calculate the head water at entrance of box culvert (2x2 m & 30 M length)
shown in Fig.2 for discharge (Q=6m'/sec)
Use the following data:
-head loss coefficient at entrance ( Ke=0.5 )& for down stream (Kd-1 )
-Manning's coefficient n=0.013.
Ke=0.5 HW
S=0.3%
2.2m
Kd=1
0.0
Fig2
L=30m

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Step 3

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 3 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

A square concrete conduit having a side of 0.788 m carries water at a rate of 4 m3/s. Using Hazen-Williams formula with C=120, a.Compute for the hydraulic radius b.Compute the hydraulic slope. c.Compute the Head loss if the length of the conduit is 45m.
A 450 mm diameter culvert has been designed to convey a discharge of Q = 0.55 m3/s of storm-water under a residential road. The culvert is 37.5 m long and has a slope of 1.3%. The downstream flow depth was obtained as 0.35 m from a hydraulic analysis. You are required to determine:1.1 the head required to convey the discharge through the culvert at full flow conditions;(a) If concrete pipe is used with a Manning’s roughness coefficient of n = 0.0155 with an inlet headwall of socket type. (b) If corrugated steel pipe is used with a Manning’s roughness coefficient n=0.024 with an inlet headwall of square edge design. 1.2 What is the corresponding headwater depth in 1.1 (a) and (b) above?
In a circular channel 2.5meters in diameter, flowing below half full, the water surface width is 2.415meter in length. a.Compute the hydraulic radius. b.The channel is laid on a grade of 24.146meters per mile; compute its discharge using Manning’s formula withn= 0.025. c.For flow as in (b), compute the C value in the Chezy formula. d.Using C in (c), and for flow as in (b), compute the value of Kutter’s nin the Kutter’s C formula. Simplify your solution, no solution by calculator or shift solve. e.Compute the maximum velocity that may occur for the given circular channel using as in (d) and Manning’s formula.
1) A triangular section has a side slope of s = 2, Manning's n = 0.02, Bottom slope of S0 = 0.005, depth, y = 2 m. Using Manning's equation (Eq. 24 in formula sheet) determine the flowrate Q. Use the Table in the last page to calculate A, and Rh (Hydraulic Radius) 2) Do the same for a rectangular section with B0 = 4 m, n = 0.015, S0 = 0.0025, and depth, y = 2 m.
A trapezoidal channel of 2.0m bed width and 3:2 side slope carries a discharge of 10m3/sec with a depth of flow of 0.5m. Determine whether the flow is supercritical or subcritical. If hydraulic jump where to form. what would be its height and efficiency. Assume mannings coefficient n = 0.025
For the concrete Dam shown in figure, determine the total average seepage for the given permeable strata by drawing Flow Net. The detail dimensions are given on the figure. The head of water on upstream side is 6ft and on downstream side is 1ft. Assume of Nf= 3, Nd= 6 and rectangular flow elements
Q1#: For the concrete Dam shown in figure, determine the total average seepage for the given permeable strata by drawing Flow Net. The detail dimensions are given on the figure. The head of water on upstream side is 6ft and on downstream side is 1ft. Assume of Nf= 3, Nd= 6 and rectangular flow elements. Use paint or graph paper. SIR PLS, GIVE ME PROPER AND CORRECT ANSWER WITH FULL DETAILS AND ALSO USE PAINT OR GRAPH PAPER. THANKS
Q#4 : For the concrete Dam shown in figure, determine the total average seepage for the given permeable strata by drawing Flow Net. The detail dimensions are given on the figure. The head of water on upstream side is 6ft and on downstream side is 1ft. Assume of Nf= 3, Nd= 6 and rectangular flow elements. Use MSpaint or graph paper
Assume uniform flow through a half-full circular channel. a. hydraulic radius (m) b. Reynolds number c. hydraulic depth (m) d. Froude number
Water flows from left to the right reservoir at a rate of 16 ft3/s (cfs). The head loss can be calculated as hL = 0.02(L/D)(V 2/2g), where L is the length of a pipe and D is the diameter. Determine the water surface elevation of the left reservoir.
Q#1(a) Water flows over a rectangular weir 3m long. The height of water surface over the weir is 1m. Calculate discharge over the weir by: Simple formula Francis’ formula Take Cd=0.62 and velocity of approach=2m/sec. Find the difference between the two discharges. (b) What is meant by “Hydraulic coefficient”? Explain different types of hydraulic coefficients. (c) What is a “Cippoletti weir” ?Prove that the side slope of a Cippoletti weir is 1:4.
Read the question carefully and give me both a&b right solutions. A 1.3-m wide rectangular channel with a bed slope of 0.00019 has a depth of flow of 0.8m. Manning’s roughness coefficient is 0.017. (a) Can Manning’s equation be applied to this system (i.e., is the flow fully turbulent)? (b) Regardless of the answer to part a, determine the steady uniform discharge in the channel.