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- Q12,A short rectangular column 300 mm on one side and 400 mm on the other side. It is reinforced with 8-16-mm-diameter longitudinal bars equally distributed to the shorter sides of the column. Use f’c = 21 MPa and fy = 420 MPa. calculate the required spacing (mm) of laterial ties 10-mm diameter. a. 300 b. 250 c. 450 d. none of the aboveA flooring system consists of parallel I-beam sections spaced at 3 m on centerswith simple spans of 6 m. The beam supports a 200 mm thick slab. The flooring system isdesigned for a live load of 2400 N/m2 as well as ceiling load of 750 N/m2. The propertiesof the I=beam sections are: d = 352mm, Ix = 0.00012m4, W = 44.85 kg/m, Fy = 248MPa, E =200,000 GPa. Use Wt. of concrete = 24kN/m3 1. Which of the following gives the uniform pressure acting on the slab. 2. Which of the following gives the total uniform load carried by a beam in kN/m. 3. Which of the following gives the maximum flexural stress on the steel beamconsidering non-composite action.
- A short rectangular column 300 mm on one side and 400 mm on the other side is reinforced with 8-16-mm-diameter longitudinal bars equally distributed to the shorter sides of the column. Use fc = 21 MPa and fy = 420 Mpa. Calculate the required spacing in mm of laterial ties 10-mm-diameter A. 300 B. 250 C. 450 D. None of the abovecolumn section = ISHB 450 Bracket plate thickness in mm =11 p=450KN E=330mm p=55mm bolt size =M2016 A short rectangular column 300 mm on one side and 400 mm on the other side is reinforced with 8-16-mm-diameter longitudinal bars equally distributed to all sides. Use f’c = 21 MPa and fy = 420 MPa. Calculate the required spacing (mm) of laterial ties 10-mm-diameter. A. 300 B. 250 C. 450 D. none of the above