Q4. In the given circuit obtain Norton's equivalent as viewed from terminal (i) a and b, (ii) с and d а ww 120 V 6 A Answer: Between a and b, 7 A, 2 Q Between c and d, 12.667 A, 1.5 Q

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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7:31 PM O
LTE
e BEE-F3-Assig..
i
20 V
10Ω
5Ω
Answer: VTh = 0 V, RTh = 10 Q, ix = 0 A
Page 2 of 2
Q4. In the given circuit obtain Norton's equivalent as viewed from terminal (i) a and
b, (ii) c and d
b
4Ω
120 V
6 A
2Ω
Answer: Between a and b, 7 A, 2 Q
Between c and d, 12.667 A, 1.5 Q
Q5. Use superposition theorem to solve for v, in the circuit.
6 A
4 A
8Ω
4ig
Answer: vy = - 80/3 V
Q6. The variable resistance R is adjustable untill it absorbs maximum power from
the circuit. (i) Calculate the value of R form maximum power, (ii) Determine the
maximum power absorb by R.
80 Ω
20 Q
40 V
R
10Ω
90 2
Answer: R = 25 Q, Maximum power = 7.84 W
2/2
Transcribed Image Text:7:31 PM O LTE e BEE-F3-Assig.. i 20 V 10Ω 5Ω Answer: VTh = 0 V, RTh = 10 Q, ix = 0 A Page 2 of 2 Q4. In the given circuit obtain Norton's equivalent as viewed from terminal (i) a and b, (ii) c and d b 4Ω 120 V 6 A 2Ω Answer: Between a and b, 7 A, 2 Q Between c and d, 12.667 A, 1.5 Q Q5. Use superposition theorem to solve for v, in the circuit. 6 A 4 A 8Ω 4ig Answer: vy = - 80/3 V Q6. The variable resistance R is adjustable untill it absorbs maximum power from the circuit. (i) Calculate the value of R form maximum power, (ii) Determine the maximum power absorb by R. 80 Ω 20 Q 40 V R 10Ω 90 2 Answer: R = 25 Q, Maximum power = 7.84 W 2/2
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