***** Q5: Two water reservoirs with difference in elevation of 25m are connected by 300m of clean wrought-iron pipe (e -0.046mm) as shown in figure below. What size must the pipe be to convey 250 L/s, v-1.0 x10 m³/s. Neglect minor losses. Water ***** Wrought-ou pipe, c-0046 m 25 m Water

* Q5: Two water reservoirs with difference in elevation of 25m are connected by 300m of clean wrought-iron pipe (e -0.046mm) as shown in figure below. What size must the pipe be to convey 250 L/s, v-1.0 x10 m³/s. Neglect minor losses. Water * Wrought-ou pipe, c-0046 m 25 m Water

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Open Channel Flow

Open channel flow is a branch of fluid mechanics. It deals with the flow of fluid in an open conduit or free surface. In an open channel flow, gravity induces the flow of water whose surface is open to the air. This flow is free-falling rather than confined in rigid body conduits. The open channel flow depends upon two parameters that are the cross-section of the conduit and the velocity profile. Practical examples of open channel flow are streams, rivers, canals, and other drainage systems.In open channel flow, the cross-sectional area of at least one of the sides is exposed to air, and the surface of water faces atmospheric pressure. This flow is also known as free gravity flow. The cross-sectional area of the conduit can be either man-made or a natural channel. For instance, the flow in rivers and streams are natural conduits, and the flow in a canal and sanitary systems are man-made or engineered channels.

Question

Traffic engineering ضخعذني

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Q5: Two water reservoirs with difference in elevation of 25m are connected by 300m of
clean wrought-iron pipe (e=0.046mm) as shown in figure below. What size must the pipe
be to convey 250 L/s, v=1.0 x10 m³/s. Neglect minor losses.
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DOM
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0.06
0.05
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Water
Twin
Wirtuagint-iron pipe, e n {1 1940 1941
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4500
25 m
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Step 1: Given

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Step 2: Apply Bernoulli equation between water surface elevation of both reservoirs

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Step 3: Use head loss equation and perform iterations to calculate pipe diameter

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