Q6 Hack memory-mapped I/O Fill the blanks The base RAM address for the Hack Screen memory map is 16384. The function pixel_clear(row, col) clears a pixel. pixel_clear(row, col) = (150, 275) is achieved by setting bit number at the RAM address to the value Bit number Only write the number. Enter your answer here

Q6 Hack memory-mapped I/O Fill the blanks The base RAM address for the Hack Screen memory map is 16384. The function pixel_clear(row, col) clears a pixel. pixel_clear(row, col) = (150, 275) is achieved by setting bit number at the RAM address to the value Bit number Only write the number. Enter your answer here

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter6: System Integration And Performance

Section: Chapter Questions

Problem 5VE

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instruction is in the first picture cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0 : CB1 | CB2 | CB 3 | ... | CB N// Set 1 : CB1 | CB2 | CB 3 | ... | CB N// ...// Set M-1 : CB1 | CB2 | CB…
When a request exceeds the cache's capacity, the CPU sends the data to main memory and the write buffer returns it. Next steps?
the available space list of a computer memory is specified as follows: 9 start address block address in words 100 50 200 150 450 600 1200 400 determine the available space list after allocating the space for the stream of requests consisting of the following block sizes: 25,100,250,200,100,150 use i) first fit ii) best fit and iii) worst fit algorithms
Operating System Memory Management: Dynamic Memory Partitioning & Paging Algorithm Order of incoming memory:a. P1 allocation 9MB,b. P2 allocation 9MB,c. P3 allocation 9MB,d. P4 allocation 3MBe. Unallocate P4 3MBg. Take off P1 Create a dynamic memory partitioning algorithm, then circle where P3 is located using the following algorithm: a. Worst-Fit b. Best-Fit c. First-Fit
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instruction is in the first picture please give me only implementation of int L1lookup(u_int32_t address) and int L2lookup(u_int32_t address) cacheSim.h #include<stdlib.h>#include<stdio.h>#define DRAM_SIZE 1048576typedef struct cb_struct {unsigned char data[16]; // One cache block is 16 bytes.u_int32_t tag;u_int32_t timeStamp; /// This is used to determine what to evict. You can update the timestamp using cycles.}cacheBlock;typedef struct access {int readWrite; // 0 for read, 1 for writeu_int32_t address;u_int32_t data; // If this is a read access, value here is 0}cacheAccess;// This is our dummy DRAM. You can initialize this in anyway you want to test.unsigned char * DRAM;cacheBlock L1_cache[2][2]; // Our 2-way, 64 byte cachecacheBlock L2_cache[4][4]; // Our 4-way, 256 byte cache// Trace points to a series of cache accesses.FILE *trace;long cycles;void init_DRAM();// This function print the content of the cache in the following format for an N-way cache with M Sets// Set 0…
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