Q8. Given that y₁ (x) = ex is a solution of xy" - (2x + 1)y + (x + 1)y=0, x>0 then a second linearly independent solution is y₂(x) = A) x³ ex B) x¹ ex C) xe* D) x5 ex E) x² ex
Q8. Given that y₁ (x) = ex is a solution of xy" - (2x + 1)y + (x + 1)y=0, x>0 then a second linearly independent solution is y₂(x) = A) x³ ex B) x¹ ex C) xe* D) x5 ex E) x² ex
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter2: Equations And Inequalities
Section2.7: More On Inequalities
Problem 44E
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![Q8. Given that y₁ (x) = e* is a solution of
xy" - (2x + 1)y + (x + 1) = 0,
then a second linearly independent solution is y₂(x) =
A) x³ ex
B) x¹ ex
C) xe*
D) x5 ex
E) x² ex
x>0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd0dd13f7-5c30-4274-a09e-9f0e5da8d84a%2F88c1c079-b497-42f6-870c-4afc544c7681%2Fv7xg4gu_processed.png&w=3840&q=75)
Transcribed Image Text:Q8. Given that y₁ (x) = e* is a solution of
xy" - (2x + 1)y + (x + 1) = 0,
then a second linearly independent solution is y₂(x) =
A) x³ ex
B) x¹ ex
C) xe*
D) x5 ex
E) x² ex
x>0
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