QI/ According to the following table the readings were taken with a level start from B.M with elevation (237.707), calculate the elevation for all points by Height of instrument method. points B.S 2.75 I.S F.S Elev. 237.707 2 1.372 3.203 2.042 1.475 4 2.655 2.816 5 0.841 6. 2.796 1.463 1.118 3.316 8 2.93 9. 1.825 2.224 1o anned with CanScanner 3.005

QI/ According to the following table the readings were taken with a level start from B.M with elevation (237.707), calculate the elevation for all points by Height of instrument method. points B.S 2.75 I.S F.S Elev. 237.707 2 1.372 3.203 2.042 1.475 4 2.655 2.816 5 0.841 6. 2.796 1.463 1.118 3.316 8 2.93 9. 1.825 2.224 1o anned with CanScanner 3.005

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Given:Upper reading = 1.64 mMiddle reading = 1.57 mLower reading = 1.51 mVertical Middle Angle = 10°32’00”Elev of point A = 333 mH of instrument = 1.2 mK = 100Stadia Constant = 0 Solve the ff.: A. Inclined, horizontal, and vertical distance B. Elevation of point B.
A line of level is run from B.M.I (elevation=106.40m) to B.M. 2 elevation=110.50m). The lield observations were recorded as given below:
A magnetic bearing of N5430’E was observed along a line XY in July1982. The declination for the area surveyedis found by interpolation from isogonic chartdated 1975 to be 1730’W with an annualchange of 01’ westward. 1. Compute the change of declination ofthe line.a. 007’W c. 037’Wb. 730’W d. 023’W 2. Compute the true bearing of the line.a. 7153’ c. 7207’b. 3700’ d. 3707
Question 16 The interior angles of a hexagon were observed and recorded as follows: A= 122 deg 31’02”, B= 123 deg 26’17”, C=130 deg 05’07”, D=120 deg 15’7”, E= 160 deg 50’35” and F= 62 deg 53’07”. The discrepancy of the measurement is Choose here A = 1’30” B= 0’30” C= 2’30” D=1’00” E=2’50” F= 1’15”
Q#1: A profile levelling is carried out and consecutive readings were observed on staff rod along a chain line at common interval of 10 meter which are listed below in table. First reading is taken on bench mark of 105.615 meter reduce level. Station Points Chainage (m) Staff Readings (m) Remarks BS IS FS 1 00 3.005 BM 2 10 2.285 3 20 1.560 4 30 1.785 5 40 2.105 6 50 2.875 3.105 CP 1 X 53.35 3.465 7 60 3.955 8 70 3.120 9 80 3.015 10 90 2.580 11 100 1.955 CP 2 Determine the reduce levels of all points using both line of collimation and rise and fall method. (Present your answer in table form).
SITUATION E: The following are the observed data for an open compass traverse. Determine the adjusted bearing of line FG, CD, and BC. Line Length Observed Bearing Forward Backward AB 452.50 m S 40°25’ W N 40°30’ E BC 405.65 m S 55°40’ W N 55°50’ E CD 495.08 m N 36°15’ W S 35°55’ E DE 284.15 m N 73°10’ W S 73°30’ E EF 367.29 m S 44°45’ W N 44°45’ E FG 217.73 m S 20°30’ E N 21°00’ W
A transit with a stadia interval factor of 100.8 was set at C on the line between points A and B, and the following stadia readings were observed. Position of Rod Vertical Angle Hair Readings in meter Upper Middle Lower Rod at A +15°35' 1.330 1.175 1.020 Rod at B -8°08' 1.972 1.854 1.736 If the stadia constant is 0.381 m, determine the following: a. Length of line AB b. Difference in elevation between points A and B c. Find the horizontal distance from the transit to the rod held at B.
STA BS FS 1 5.87 2 7.03 6.29 3 3.48 6.25 4 7.25 7.08 5 10.19 5.57 6 9.29 4.45 7 4.94 a. Determine the elevation at Sta. 7, in meters if the elevation at station 1 is 392.25m. b. Determine the elevation of the instrument where the surveyor can get readings from stations 3 and 4.
Answer using moment distribution method. Use second picture as guide W= 25P1 = 25P2 = 25
1Q is 18 7T is 72
Measurement of three horizontal angles about point P: are APB= 12°31'50'' BPC= 37°29'20'', and CPD= 47°36'30''. If the measurement of the single angle APD is 97°37'00'', determine the most probable values of the angles.
Given the following data, convert heading to azimuth or vice versa, leave procedure. 1) If the azimuth of A-B is 45°32', then the heading of A-B is: 2) If the azimuth of A-B is 295°25', then the heading of A-B is: 3) N17°45'10" 4) S45°20'12" 5) 130°19'10"