Question 1 Blank 1 Blank 2 Blank 3 What will be printed after executing the following C++ code? int tt[] = { -5, -8, 7 }; 4, 6 }; int dd [] = { 3, int rst[3]; for (int i = 2; i >= 0; i--) {rst[i]= dd[i] - tt[i]; cout << rst[i] << '\n'; }
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- Consider the following segment of code:procedure Mvar x: integer;procedure A (c: integer)var a, b: integer;procedure Bvar b, c, d: integer;begin {B}….a := c – d;….end B;begin {A}….x := b + c;….B()….end A;begin {M}….A(3)….end M;Assuming the definition of M is at static nesting level 0. Draw the runtime stack that will be ineffect at the execution of “a := c – d;”. Show the static and dynamic links, and the currentpositions of the EP and SP pointers.What is the static distance to x’s environment of definition and the offset within the environmentwhen “a := c – d;” is executed?Write a program in C/C++ that reads N number of nonnegative decimal numbers from a user and creates a hash table to store the numbers. The output of the program displays the order of the numbers in the hash table. The program then prompts the user to enter a target value. The program searches the target value to the hash table, and displays the search outcome. For simplicity, let’s assume that N = 6 and the size of the hash table is 10. Use this hash function in your code h(k) = 2k+3 where k is the key value. Use linear probe method for collision resolution. Example test run Test Run 1: Enter 6 elements: 3 2 9 6 11 13 Hash table order: 13 9 - - - 6 11 2 - 3 Enter the target: 1111 is located at index: 6 Test Run 2: Enter 6 elements: 3 2 9 6 11 13 Hash table order: 13 9 - - - 6 11 2 - 3 Enter the target: 1515 is not in the table6.Need ri Write a JAVA program that will maintain a phone directory using a Linked-List. The program should be able to perform the following operations: Add persons details (first name, last name, phone number, city, address, sex and email) to the phone directory, where phone numbers in the directory have to be unique. (Note: each person record will store in one node in the linked-list and insert each person to the last) Delete any person details by a given phone number. Update telephone number by providing person first name. Display all details of persons from a phone directory. Search telephone number based on person first name. (Note: use sequential search to find all telephones for the given first name) Sort all persons in the phone directory ascending based on person first name. (Note: use bubble or selection sort to arrange the entire phone directory.
- I am learning C for a class I am taking and a homework assignment asks us to makes a list of integers, divides the list into a number of segments, and displays each segment in reverse order. We need to use the function malloc to dynamically allocate locations for variables a and b. The full assignment is below. I am not too familiar with C and I don't know how to split the list into two arrays.The famous Sudoko game is played on a grid of 9 ×9. Each empty square in this grid has to befilled with a number from 1 – 9 without repeating any numbers within the row and column of thesquare. We will implement a program in C to help us solve a simple 4 ×4 Sudoko puzzle. We willinvestigate a 4 ×4 Sudoko puzzle, where each row or column is missing 2 numbers only. To fill ina square, if you scan the row (or column) of the square, you will eliminate two out of 4 numbers,and if you then scan the column (or row) of the square, you will eliminate one more number. Thus,you will be left with one missing number in the row and column of the empty square. Thus, youneed to fill in the square with this missing number. We are NOT studying the case where scanningthe row and column of a square eliminates only 2 numbers.For example, in the following grid, row 0 and column 0 is empty. If we scan row 0, we can eliminate3 and 4 since they are already there in the row. And if we scan the column, we can…) Consider the following C code snippet. void swap(int *xp, int *yp) { int temp = *xp; *xp = *yp; *yp = temp; } int findMinimum(int arr[], int N) { // variable to store the index of minimum element int min_idx = 0; int min_E = arr[min_idx]; // Traverse the given array for (int i = 1; i < N; i++) { // If current element is smaller than min_idx then update it if (arr[i] < min_E) { min_idx = i; min_E = arr[min_idx]; } } return min_idx; } /* Function to sort an array using selection sort*/ void selectionSort(int arr[], int n) { int i, min_idx; // One by one move boundary of unsorted subarray for (i = 0; i < n-1; i++) { // Find the minimum element in unsorted array min_idx = findMinimum(&arr[i], n-i); // Swap the found minimum element with the first element if(min_idx != 0) swap(&arr[min_idx+i], &arr[i]); } }…
- A Java Program Write a method called samePosition in a class called StackExt that receives two parameters st1 and st2 of type ArrayStack and a third parameter pos of type int. The method returns true, if stack st1 and st2 contains the same value in position pos. Otherwise, the method returns false. Assume that both stacks st1 and st2 contain same number of elements. Assume that the position of the top element is 0 and increases by 1 for each subsequent element. The elements of both stacks st1 and st2 must remain in the original relative positions in the stacks at the end of the method. Use common stack operations only such as push, pop, peek, isEmpty, constructor and copy constructor. You can create temporary objects of type ArrayStack in your method. Example: top st1: 4 5 3 10 8 st1: 5 9 4 10 1 If the pos is 3, then both stacks contain 10 in position 3. The method returns true. If the pos is 1, then st1 contains 5 and st2…Write the C equivalent “train” function #void train(int*A, int*B, int*C, int k) train: add $t4, $0, $0bus: add $t5, $t4, $a1 lw $t6, 0($t5) add $t5, $t4, $a2 lw $t7, 0($t5) add $t6, $t6, $t7 add $t5, $t4, $a0 sw $t6, 0($t5) addi $t4, $t4, 4 slt $t5, $t4, a3 bne $t5, $0, bus jr raYou are required to demonstrate the running time difference between a linked listand a binary search tree while searching the data. Read the following instructionsand then implement a C++ program that can address the above requirement.1- choose byself a .csv file containing the data named Dataset.csv The dataset file contains a record of 100000 sales records of astore. By using the text file reading method in C++, read the data of the file in alinked list and a binary search tree. (In a single program) After reading the data validate the data reading by implementing a print() method. Take a sales id as an input from the user and search that ID in the linked listand binary search tree. Display the running time difference of both data structures during the searchoperation.
- Implement the function below. void swap(int pos1, int pos2){} Initial code to be completed: class ArrayList : public List { int* array; int index; int capacity; void dyn_all_add(){ int cap = ceil(capacity * 1.5); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } void dyn_all_rem(){ int cap = capacity - (capacity/3); array = (int*)realloc(array,cap * sizeof(int)); capacity = cap; } public: // CONSTRUCTOR ArrayList() { capacity = 4; array = (int*)malloc(capacity); index = 0; } int add(int num) { if (index == capacity){ dyn_all_add(); } *(array + index) = num; index++; return index; } int get(int pos){ if (pos-1 < index){ return *(array + pos-1); } return -1; } int size(){ return index; }…write in C for a STM32F446RE microcontroller Write a source library that contains the with the following public functions: void keypadInit(void); /Initiallized the GPIO to read the keypad. uint16_t readKeypad(void); //Returns the state of all of the keypad buttons in the return value at the moment the function is called. void decodeKeypad(uint16_t, char *); //Takes the state of the keypad and returns (by reference) an array of the key's pressed. The library should work with the following main: int main (void) { uint16_t key; char carray[17]; keypadInit(); while(1) { while(!(key = readKeypad())); /*Get which keys pressed*/ decodeKeypad(key, carray); /*What are those keys*/ printf("%s\n",carray); /*Print those keys to screen*/ while(readKeypad() == key); /*Wait for the keypad to change*/ }} Problem 1: Write a library that works with the following pin assignments Row 0 -> PC0 Row 1 -> PC2 Row…Write a C++ program that: (1) defines and implements a hash class that constructs a 15 element vector, storing strings, using the following hash function: ((first_letter) + (last_letter) - (second_letter))% 15 So, for example, the word "rocky" would be ('r') = 114 + ('y') = 121 - ('o') = 111 = 124%15 = 4 In this example, an attempt would be made to store "rocky" in position 4. In the event of a collision, the word would be stored in the first available location, so if there is a collision in location 4, an attempt would be made to store the word in location 5. If an attempt to store a word in position 14 fails because the location is full circle back to location 0 because there is no location 15. If there is a collision in location 0, try location 1, and so on. I will not try your program with words that are shorter than three letters, so you do not need to consider shorter words. (2) the driver program should: a. query the user for ten words and store them…