Question 1 For the field A = 5 cos (4) 2 the integral along the path (2, /3, 5) to (2, 1/2, 5) is equal to: %3D OA. V3 10 cos () do = 10( 1) %3! x/2 O B. None of the Given answers O C. zero D. 10 cos (4) do = = 10(1– z13

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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Question 1
For the field
A = 5 cos (4) 2
the integral along the path (2, /3, 5) to (2, T1/2, 5) is equal to:
O A.
| 10 cos (4) do = 10(
1)
!!
x/2
2
O B. None of the Given answers
O C. zero
D.
2/2
10 cos (4) dø :
= 10(1–
21
13
Transcribed Image Text:Question 1 For the field A = 5 cos (4) 2 the integral along the path (2, /3, 5) to (2, T1/2, 5) is equal to: O A. | 10 cos (4) do = 10( 1) !! x/2 2 O B. None of the Given answers O C. zero D. 2/2 10 cos (4) dø : = 10(1– 21 13
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