Question 1 of 15 View Policies Current Attempt in Progress Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, ef (a) dar = cF(2) + C. (b) An antiderivative of a sum is the sum of the antiderivatives; %3D that is, S(z) + g(z)] dx = F(x)+ G(x)+ C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, s (z) – g(x)| de = F(x) – G(x) + C. %3D The power rule: x dx +C,r # -1. r+1 %3D NOTE: Enter the ezact answer. S da = 825 11x + +C

Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter4: Polynomial And Rational Functions
Section4.3: Zeros Of Polynomials
Problem 67E
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Question 1 of 15
View Policies
Current Attempt in Progress
Evaluate the integral by applying the following theorems
and the power rule appropriately.
Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x)
respectively, and that c is a constant. Then:
(a) A constant factor can be moved through an integral sign; that is,
|ef(z) dz = cF(x) + C.
%3D
(b) An antiderivative of a sum is the sum of the antiderivatives;
that is,
S(z) + g(x)] dx = F(x)+ G(x)+C.
(c) An antiderivative of a difference is the difference of the
antiderivatives; that is,
is(z) – g(x)| de = F(x) – G(x) + C.
%3D
The power rule:
x dx
+C,r # -1.
r+1
%3D
NOTE: Enter the ezact answer.
dz =
825
11x +
+C
Transcribed Image Text:Question 1 of 15 View Policies Current Attempt in Progress Evaluate the integral by applying the following theorems and the power rule appropriately. Suppose that F(x) and G(x) are antiderivatives of f(x) and g(x) respectively, and that c is a constant. Then: (a) A constant factor can be moved through an integral sign; that is, |ef(z) dz = cF(x) + C. %3D (b) An antiderivative of a sum is the sum of the antiderivatives; that is, S(z) + g(x)] dx = F(x)+ G(x)+C. (c) An antiderivative of a difference is the difference of the antiderivatives; that is, is(z) – g(x)| de = F(x) – G(x) + C. %3D The power rule: x dx +C,r # -1. r+1 %3D NOTE: Enter the ezact answer. dz = 825 11x + +C
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