Question 14 Find the solution. (D3 - 3D - 2)y =0; when x =0, y=0, y' = 9, y" = 0. A y = (-1+ 2r)e-2x+e2x B y = (-1+ 2x)e2* + 2e¬x (c) y = (-2 + 3x)e+2e2* D y = (-2 + x)e-+2e*

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