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QUESTION 14 Given is PDA a, Z/xZ 90 ja, x/xx 91 b, X/e e, z/e 92 b, X/e e = epsilon This is a valid computation: (q0, aaaabbbb, Z) |-* (q0, ɛ, E). O True False QUESTION 15 Two CFGS, G1 and G2, are given: S-> as | Sb | a | b G1: and G2: S -> asbs | bSas | e (read e as "epsilon") Which grammar(s) produces the set of strings with equal numbers of a's and b's. O A. G1 and G2. B. Only G1. OC. Only G2. O D. None.

QUESTION 14 Given is PDA a, Z/xZ 90 ja, x/xx 91 b, X/e e, z/e 92 b, X/e e = epsilon This is a valid computation: (q0, aaaabbbb, Z) |-* (q0, ɛ, E). O True False QUESTION 15 Two CFGS, G1 and G2, are given: S-> as | Sb | a | b G1: and G2: S -> asbs | bSas | e (read e as "epsilon") Which grammar(s) produces the set of strings with equal numbers of a's and b's. O A. G1 and G2. B. Only G1. OC. Only G2. O D. None.

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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QUESTION 14 Given is PDA a, Z/xZ 90 ja, x/xx 91 b, X/e e, z/e 92 b, X/e e = epsilon This is a valid computation: (q0, aaaabbbb, Z) |-* (q0, ɛ, E). O True False QUESTION 15 Two CFGS, G1 and G2, are given: S-> as | Sb | a | b G1: and G2: S -> asbs | bSas | e (read e as "epsilon") Which grammar(s) produces the set of strings with equal numbers of a's and b's. O A. G1 and G2. B. Only G1. OC. Only G2. O D. None.
Transcribed Image Text:QUESTION 14 Given is PDA a, Z/xZ 90 ja, x/xx 91 b, X/e e, z/e 92 b, X/e e = epsilon This is a valid computation: (q0, aaaabbbb, Z) |-* (q0, ɛ, E). O True False QUESTION 15 Two CFGS, G1 and G2, are given: S-> as | Sb | a | b G1: and G2: S -> asbs | bSas | e (read e as "epsilon") Which grammar(s) produces the set of strings with equal numbers of a's and b's. O A. G1 and G2. B. Only G1. OC. Only G2. O D. None.
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